Answer:
The first question should be "What is the purpose of WLAN ?" .
In order to design a stable and better WLAN user should understand the purpose or intended use of WLAN.
For example : A school's wireless network will be different than the corporate wireless network.
In order to design the WLAN in a better way . User should know following
1. What is the purpose of the WLAN ?
2. How many users will be using it at a time ?
3. How many users will use it over all given a period of time ?
4. What are the common applications being used ?
5. Who will be using the WLAN?
6. Is there any legacy devices that need backward compatibility ?
So unless user doesn't understand the complete purpose and requirement of the WLAN, it is not possible to give the best design for the same. Capacity and Coverage needs to be taken care while designing WLAN.
Explanation:
as explained above.
Answer:
a)
#include <iostream>
using namespace std;
int main() {
bool a,b,c;
cin>>a>>b;
if(a^b)//X-OR operator in C++.
c=true;
else
c=false;
cout<<c;
return 0;
}
b)
#include <iostream>
using namespace std;
int main() {
bool a,b,c,d;
cin>>a>>b>>c;
if((a^b)^c)//X-OR operator in C++.
d=true;
else
d=false;
cout<<d;
return 0;
}
Explanation:
The above written programs are in C++.There is an operator (^) called X-OR operator in C++.It returns true if the number of 1's are odd and returns false if the number of 1's are even.
In the if statement I have user X-OR operator(^) to find the result and storing the result in another boolean variable in both the questions.
2000 nibbles I think correct me if I’m wrong
Answer:
To make sure that there is no other outside/excess noise while you are filming your actual film
Hoped this helped !
Cheers, Z
