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scZoUnD [109]
3 years ago
11

Why when i click home on iphone i still at my grandma house

Computers and Technology
2 answers:
andrey2020 [161]3 years ago
5 0

Answer:

The home button on your phone takes you to the home screen of your iphone, not your home in real life.

I know this was I joke I just gotta get those points ya know?

kramer3 years ago
3 0

Answer:i don't know

Explanation:

You might be interested in
Write a function chat accepts a pointer to a C-string as its argument. The function should count the number of vowels appearing
Dovator [93]

Answer:

Function contains into the code asked for:

  • Receives a string as an argument.  
  • count the number of vowels in the string and return that number.
  • receives a string as an argument.
  • count the number of consonants in the string and return that number.  

Explanation:

//Let's call libraries

#include <stdio.h>  

#include <conio.h>

//Start main

int main()

{

//*Declare functions for counting number of vowels and consonants

int vowels=0;      

int consonants=0;    

int all=0;    

//Output need information

//Ask user to input a string

printf("what do you want to count?\n");    

printf("1-the vowels.\n");      

printf("2-the consonants.\n");    

printf("3-all of the letters on a phrase.\n");      

printf("\n");      

printf("-> ");      

int a;    

a = getchar();

   switch (a)

   {          

//Ask user what function they want to run

case '1':

//Call the function needed to count the vowels  

            printf("Introduce a phrase: ");                  

char textoa[1001];                

scanf("%s", &textoa);

char *p;                  

p = textoa;                

while (*p != '\0')

               {

                     if (*p == 'a' || *p == 'e' || *p == 'i' || *p == 'o' || *p == 'u' || *p == 'A' || *p == 'E' || *p == 'I' || *p == 'O' || *p == 'U') vocales ++;

                     p++;

               }

               printf("there are %d vowels.", vowels);                  

break;            

case '2':

//Call the function needed to count the consonants

printf("Introduce a phrase: ");                

char textob[1001];                

scanf("%s", &textob);

p = textob;                

while (*p != '\0')

               {

                     if (*p == 'b' || *p == 'B' || *p == 'c' || *p == 'C' || *p == 'd' || *p == 'D' || *p == 'f' || *p == 'F' || *p == 'g' || *p == 'G' || *p == 'h' || *p == 'H' || *p == 'j' || *p == 'J' || *p == 'k' || *p == 'K' || *p == 'l' || *p == 'L' || *p == 'm' || *p == 'M' || *p == 'n' || *p == 'N' || *p == 'p' || *p == 'P' || *p == 'q' || *p == 'Q' || *p == 'r' || *p == 'R' || *p == 's' || *p == 'S' || *p == 't' || *p == 'T' || *p == 'v' || *p == 'V' || *p == 'w' || *p == 'W' || *p == 'x' || *p == 'X' || *p == 'y' || *p == 'Y' || *p == 'z' ||  

*p == 'Z') consonants ++;

                     p++;

               }

               printf("there are %d consonants.", consonants);                  

break;            

case '3':

printf("Introduce a phrase: ");                

char textoc[1001];                

scanf("%s",&textoc);

p = textoc;                

while (*p != '\0')

               {

                     if (*p == 'a' || *p == 'e' || *p == 'i' || *p == 'o' || *p == 'u' || *p == 'A' || *p == 'E' || *p == 'I' || *p == 'O' || *p == 'U' || *p == 'b' || *p == 'B' || *p == 'c' || *p == 'C' || *p == 'd' || *p == 'D' || *p == 'f' || *p == 'F' || *p == 'g' || *p == 'G' || *p == 'h' || *p == 'H' || *p == 'j' || *p == 'J' || *p == 'k' || *p == 'K' || *p == 'l' || *p == 'L' || *p == 'm' || *p == 'M' || *p == 'n' || *p == 'N' || *p == 'p' || *p == 'P' || *p == 'q' || *p == 'Q' || *p == 'r' || *p == 'R' || *p == 's' || *p == 'S' || *p == 't' || *p == 'T' || *p == 'v' || *p == 'V' || *p == 'w' || *p == 'W' || *p == 'x' || *p == 'X' || *p == 'y' || *p == 'Y' || *p == 'z' || *p == 'Z') all ++;

                     p++;

               }

               printf("there are %d letters on the phrase.", all);                 break;

   }     getch();

}

8 0
3 years ago
In Modern operating system, the __ feature has dramatically improved user productivity.
icang [17]

Multitasking, it allows you to do more than one thing at once.

3 0
3 years ago
Tina reported a safety hazard at her workplace to OSHA. Representatives from OSHA came to her work and inspected the issue, then
earnstyle [38]

Answer:

Knowledge of hazardous workspace conditions

6 0
3 years ago
Overlay analysis is ____________, taking in data from two or more layers to create a single output layer.
Wewaii [24]

Explanation:

Overlay analysis is an approach, taking in data from two or more layers to create a single output layer.

For example, if we have a layer of land use and a layer of soil fertility, we can derive from the two layers the percentage of agricultural land developed over fertile soil.

6 0
3 years ago
What is the output of adding 1001011 and 100000?
Otrada [13]
1101011, 0x6B or 0153
7 0
3 years ago
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