Answer:
C.) 4
Step-by-step explanation:
we are given ABCD is an isosceles trapezoid
AB || CD
AB = m + 6
CD = 3m + 2
BC = 3m
AD = 7m - 16
Since, ABCD is an isosceles trapezoid
so, two sides must be equal
now, we can plug values
now, we can solve for m
Divide both sides by -4
and we get
0.4 divided by 0.242 = 0.605 then you can either multiply. 0.4 times 0.605 and get 0.242 or you can do 0.242 times 0.605 and get 0.4 either way will work
Given the position function <em>s(t)</em>, you can get the acceleration function by differentiating <em>s</em> twice:
velocity = <em>s'(t)</em> = -5 sin(<em>t </em>) + 3 cos(3<em>t</em> )
acceleration = <em>s''(t)</em> = -5 cos(<em>t</em> ) - 9 sin(3<em>t</em> )
Then when <em>t</em> = <em>π</em>, the particle's acceleration is
<em>s''(π)</em> = -5 cos(<em>π</em>) - 9 sin(3<em>π</em>)
… = -5 • (-1) - 9 • 0 = 5
Step-by-step explanation:
so we're making two draws *with* replacement (this is important)
step 1: for the first draw, it wants the probability of getting a sour candy. to calculate this:
(# of sour candy) / (total # of candy)
step 2: for the second draw, it wants the probability of *not* getting a sour candy. to calculate this, you can calculate 1 - (the probability form part 1).
step 3: to find the probability of both events happening together, simply multiply the probabilities from part 1 and 2 together
side note: for step 2, you can only do this because the candy is being replaced. if there were no replacement, you'd have to re-calculate (# of non-sour candies) / (total after the first candy is drawn)
Answer: They sold 68 tickets at the door
688-920= -2x= -232
2x=232/2=116
184-116=68
