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3 years ago

Classify scatter plot

Mathematics

1 answer:

nexus9112 [7]3 years ago

6 0

Answer:

The correct answer is B. Linear Relationship

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Which of the following is the slope of the line passing through the

julia-pushkina [17]

Answer:

I think the slope is UNDEFINED

y²-y¹/x²-x¹

(-5)-(16)/(-12)-(-12)

-21/0

=Undefined

6 0

3 years ago

Express the vector ModifyingAbove Upper P 1 Upper P 2 with right arrowP1P2 in the form Bold v equals v 1 Bold i plus v 2 Bold j

Tatiana [17]

Answer:

$\overrightarrow{P_1P_2}=-5\textbf{i}-4\textbf{j}-6\textbf{k}$

Step-by-step explanation:

$\overrightarrow{P_1P_2}=(P_2-P_1)\cdot(\textbf{i},\textbf{j},\textbf{k})=(-5-0)\textbf{i}+(-3-1)\textbf{j}+(-9-(-3))\textbf{k}\\\\\overrightarrow{P_1P_2}=-5\textbf{i}-4\textbf{j}-6\textbf{k}$

3 0

4 years ago

What are the coordinates of point B on AC such that the rario of AB to BC is 2:3

pishuonlain [190]

Answer:

Step-by-step explanation:

im not too sure buy i have the exact questions

7 0

3 years ago

Given: y" - 2y' = 6t + 5e^2t. Find the correct form to use for y_p if the equation is solved using Undetermined coefficients. Do

const2013 [10]

Answer:

$y_p=A+Bt+Ce^{2t}$

Step-by-step explanation:

Given: $y'' - 2y' = 6t + 5e^{2t}$ .

we need to find the correct form for $y_p$ if the equation is solve using undetermined coefficients.

A first order differential equation $\frac{\mathrm{d} y}{\mathrm{d} x}=f\left ( x,y \right )$ is said to be homogeneous if $f(tx,ty)=f(x,y)$ for all t.

Consider homogeneous equation $y''-2y'=0$

Let $y=e^{rt}$ be the solution .

We get $(r^2-2r)e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2-2r=0$ .

So, we get solution as $y_c=c_1+c_2e^{2t}$

As constant term and $e^{2t}$ are already in the R.H.S of equation

$y" - 2y' = 6t + 5e^{2t}$ , we can take $y_p$ as $y_p=A+Bt+Ce^{2t}$

6 0

4 years ago

Answerr for money!!!

cestrela7 [59]

Answer:

Line s and Line t are parallel.

Step-by-step explanation:

Now, we know that angles 1 and 2 are congruent, because they have the same angle measures. Now, looking at their positions, we can see that they are alternate exterior angles.

By the converse of the Alternate Exterior Angle, (I do not remember exactly how the theorem went) if two lines are cut by a transversal and have congruent alternate exterior angles, then the lines are parallel. Using this theorem, we can find that lines s and t are parallel, because they are cut by a transversal and their alternate exterior angles are congruent.

I hope you find my answer and explanation to be helpful. Happy studying.

5 0

3 years ago