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zalisa [80]
2 years ago
8

For what value of k, the following pair of linear equations has unique solution

Mathematics
1 answer:
riadik2000 [5.3K]2 years ago
8 0

Answer:

uv UC uh uh uh uh uh uh uh all tardy txt tch tch addressed to you and your family a very happy and prosperous new year and I have to go go go go go go go go go go go go in to comes to that and return to me and I will pick ⚒️⛏️ me know if you have u I love you too and miss you too babe I love it ❤️ me know when you're ready tomorrow morning to get the money to you and your team for the impostor

Step-by-step explanation:

gucci figure ucc txt ucc p on ohh I thought you were going to be a little late to the party but I love you and I thought I tttty me know if you need anything else from me please let me know if you need anything else from me please let's do that you have a great holiday season and a few others are not going me

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10 x 23 x 4 divided by 54 x 4
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Step-by-step explanation:

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put the equation through a calculator

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If clay cost $16.50 for 50lb how much does clay cost for 45 pounds
emmasim [6.3K]

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Get the general term for the sequence being your t3 = 11 and the t20 = 244.2
marusya05 [52]

Answer:

nth term = t_{n} = 7.639(1.2)^{n - 1}

Step-by-step explanation:

Let us assume that the given sequence is a G.P.

Now, if the first term of the G.P. is a and the common ratio is r, then

Third term = t_{3} = ar^{2} = 11 .......... (1) and  

20th term = t_{20} = ar^{19} = 244.2 ........... (2)

Now, dividing equation (2) with equation (1) we get

\frac{ar^{19} }{ar^{2} } = \frac{244.2}{11} = 22.2

⇒ r^{17} = 22.2

⇒ r = 1.2.

Hence, from equation (1) we get

a(1.2)² = 11

⇒ a = 7.639 (Approx.)

Therefore, the general term of the sequence i.e. nth term = t_{n} = 7.639(1.2)^{n - 1} (Answer)

5 0
3 years ago
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