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igomit [66]
2 years ago
5

A sweatshirt manufacturer includes a shipping charge of $5.99 on all online orders. Customers also pay 2.5% tax on all their pur

chases. There is a linear equation between c, the cost of of the items purchased, and t, the total cost of including shipping and tax. Which statement is true about the function that represents the relationship between c and t. Brainly
Mathematics
1 answer:
Maru [420]2 years ago
6 0

Answer:

t = 1.025c + 5.99

Step-by-step explanation:

The shipping charge, = $5.99

Tax paid on purchases = 2.5%

Cost of item, c

Total cost, t, including shipping and tax

Total cost = Cost of item + tax on purchase +. Shipping fee

Tax on purchase : 2.5% * cost of item

Tax on purchase : 0.025c

Shipping = $5.99

General formula for a linear equation :

y = mx + c

Hence, for the cost model:

Total cost = Cost of item + tax on purchase +. Shipping fee

t = c + 0.025c + 5.99

t = 1.025c + 5.99

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An athlete completes a race in 55.72 seconds. How many times greater is the digit in the tens place than the digit in the ones p
MArishka [77]
As they are the same the answer is 1 times
8 0
3 years ago
Find the mean, median and mode from the chart below ​
BlackZzzverrR [31]

Answer:

1. mean=1.5, median=1.7, mode is 1.8

2. mean=102,median=134, mode=no mode

3. mean=1885,median=2300, mode=2300

Step-by-step explanation:

6 0
3 years ago
One more time!
CaHeK987 [17]
Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}

so we conclude that
q(\frac{\sqrt{19} }{2} ) = 1/4

therefore

p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right)  \right)

plug x=\sqrt{19}/2 into p( q(x) ) to get answer

p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left(  \frac{\sqrt{19} }{2}\right)^2 }{ \left(  \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow

\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow  -\dfrac{6\sqrt{19} }{361}

p(1/4) = -\dfrac{6\sqrt{19} }{361}
3 0
3 years ago
The domain of u(x) is the set of all real values except 0 and the domain of v(x) is the set of all real values except 2. What ar
beks73 [17]

Answer:

A≈1075.21

d Diameter

37

d

r

r

r

d

d

C

A

Using the formulas

A=

π

r

2

d=

2

r

Solving forA

A=

1

4

π

d

2

=

h1

4

π

37

2

≈

1075.21009

Step-by-step explanation:

5 0
3 years ago
60 points !! i'll mark brainliest as well . don't scam or i'll report thanksss :)
sp2606 [1]

Answer:

2, 6, 28, 358.01

Step-by-step explanation:

We have to find the fractions of whole numbers.

Number 1:

\frac{1}{5} of 10 = \frac{1}{5} \times (2 \times 5) = 2 (Answer)

Number 2:

\frac{2}{3} of 9 = \frac{2}{3} \times (3 \times 3) = 2 \times 3 = 6 (Answer)

Number 3:

\frac{7}{8} of 32 = \frac{7}{8} \times (4 \times 8) = 7 \times 4 = 28 (Answer)

Number 4:

3 \times 10^{2} + 5 \times 10^{1} + 8 \times 10^{0} + 1 \times \frac{1}{10^{2} }

= 3 \times 100 + 5 \times 10 + 8 \times 1 + \frac{1}{100} {Since a^{0} = 1}

= 300 + 50 + 8 + 0.01

= 358.01 (Answer)

4 0
3 years ago
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