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andrew-mc [135]
3 years ago
6

Help a girl out please ???

Mathematics
2 answers:
Andreas93 [3]3 years ago
8 0

Answer:

1.) y= 41

2.) y=34

3.) y= -19

Step-by-step explanation:

1.) y= (15 x 3) - 40

   y= 45-40

   y= 41

2.) y= (2/3 x 21) +20

    y= 14+20

    y= 34

3.) y= (3* -2)² +17

    y= -6² +17

    y= -36 +17

    y= -19

Gnoma [55]3 years ago
4 0

Answer:

1.)

y= (15 x 3) - 40

y= 45-40

y= 41

2.)

y= (2/3 x 21) +20

y= 14+20

y= 34

3.)

y= (3* -2)² +17

y= -6² +17

y= -36 +17

y= -19

SRY I DID NOT ANSWER BEFORE

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Determine if x-6 is a zero and find the quotiant and the remainder​
sergiy2304 [10]

Answer:

○ A. No, x = -6 is not a zero of the polynomial.

The quotient is x - 29, and the remainder is 234.

Step-by-step explanation:

[x - 3][x - 20] >> Factored Form

Obviously, this is not a zero. Now, to get the remainder, we have to plug in the vertical line of <em>x = -6</em> into its conjugate, meaning an expression with opposite signs, which is <em>x + 6</em>. This is the expression we divide the dividend by, so you will have this:

\frac{{x}^{2} - 23x - 60}{x + 6}

Since the divisor is in the form of <em>x - c</em>, using Synthetic Division, we get this:

x - 29 + \frac{234}{x + 6}

You see? You have <em>x - 29</em> in the quotient, and you have 234 as the numerator remainder.

I am joyous to assist you anytime.

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3 years ago
Please answer <br><br> Simplify by dividing 3/5 ÷ -4/9
Shtirlitz [24]

Hello! :)

3/5 ÷ -4/9

= -27/30

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3 years ago
For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.
Anni [7]

Answer:

The reduced row-echelon form of the linear system is \left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

  1. Interchange two rows
  2. Multiply one row by a nonzero number
  3. Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]

You need to follow these steps:

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\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]

  • Subtract row 1 from row 2 \left(R_2=R_2-R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]

  • Subtract row 1 multiplied by 5 from row 3 \left(R_3=R_3-\left(5\right)R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 1 \left(R_1=R_1-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 3 \left(R_3=R_3-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]

  • Multiply row 2 by 2 \left(R_2=\left(2\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]

  • Divide row 3 by −19 \left(R_3=\frac{R_3}{-19}\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]

  • Subtract row 3 multiplied by 16 from row 1 \left(R_1=R_1-\left(16\right)R_3\right)

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\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

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Another way to check the sum of 104+34+228+877
vekshin1
We are asked to identify an another way to solve the given problem or this summation 104 + 34 + 228 + 887. We can verify it by doing of performing the summation in a reverse sequence such 877 comes first, then followed by 228, then followed by 34 and lastly added by 104. Therefore, the answer is 877 + 228 + 34 + 104.This is an another way to solve the given problem.
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3 years ago
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