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3 years ago

9

Sherita’s club is selling grapefruit to raise money. For every box they sell, they get $1.35 profit. They have sold 84 boxes alr

eady. How many more boxes must they sell to raise 270 dollars?

2 answers:

iragen [17]3 years ago

6 0

Answer:

the answer is 116

Oxana [17]3 years ago

5 0

Divide 270 to 1.35, you get 200. Sherita must sell 200 boxes to raise $270.

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1. Melissa took out a loan of $50,000 with an interest rate of 2.3% for the start-up of the Math Cafe. How much will she owe the

77julia77 [94]

Answer:

<em>$55,750 a</em>

Step-by-step explanation:

Given Principal P = $50,000

Rate R = 2.3%

Time T = 5 years

Get the interest first

Simple interest = PRT/100

Simple interest = 50,000*2.3*5/100

Simple interest = 500*2.3*5

Simple interest = $5,750

Amount = Principal + Interest

Amount = $50,000 + $5,750

Amount = $55,750

<em>Hence she will owe the bank $55,750 after 5 years</em>

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2 years ago

Which expression has a negative value A. 2+12 B. (-3)(-8) C. 10-(-18) D. -35÷5

alina1380 [7]

Answer:

It's D

Step-by-step explanation:

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3 years ago

Read 2 more answers

Consider the scatter plot.

julia-pushkina [17]

Answer:

A

Step-by-step explanation:

An outlier is a data point that seems like it shouldn't belong; it could be extremely small or extremely big or simply not even a part of the correlation.

Looking at the scatter plot, it's quite clear that there is one point far from the others. This will be the outlier.

Observe its coordinates; they are about (8.8, 5.2).

So, the answer is A.

Hope this helps!

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3 years ago

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Lim x->pi/3 ((2cosx-1)/(tan^2x-3))

beks73 [17]

You can check that the limit comes in an undefined form:

$\displaystyle \lim_{x\to\frac{\pi}{3}} \frac{2\cos(x)-1}{\tan^2(x)-3}=\dfrac{0}{0}$

In these cases, we can use de l'Hospital rule, and evaluate the limit of the ratio of the derivatives. We have:

$\dfrac{\text{d}}{\text{d}x}2\cos(x)-1 = -2\sin(x)$

and

$\dfrac{\text{d}}{\text{d}x}\tan^2(x)-3 = 2\dfrac{\tan(x)}{\cos^2(x)}=\dfrac{2\sin(x)}{\cos^3(x)}$

So, we have

$\displaystyle \lim_{x\to\frac{\pi}{3}} \frac{2\cos(x)-1}{\tan^2(x)-3}=\lim_{x\to\frac{\pi}{3}} \dfrac{-2\sin(x)}{\frac{2\sin(x)}{\cos^3(x)}}=\lim_{x\to\frac{\pi}{3}}-\cos^3(x)=-\cos^3\left(\dfrac{\pi}{3}\right)$

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2 years ago

What graph represents −3x+1≤10

nalin [4]

The solution of the inequality is x ≥ -3 and the graph is shown below

<h3>Graph of inequalities </h3>

From the question, we are to determine the graph that represents the given inequality

The given inequality is

−3x + 1 ≤ 10

First, we will solve the inequality

−3x + 1 ≤ 10

Subtract 1 from both sides

−3x +1 -1 ≤ 10 - 1

−3x ≤ 9

Divide both sides by -3 and<u> flip the sign</u>

x ≥ -3

The graph of the inequality is shown below

Learn more on Graphing inequalities here: brainly.com/question/13053003

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2 years ago