Answer:
IQ scores of at least 130.81 are identified with the upper 2%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 100 and a standard deviation of 15.
This means that 
What IQ score is identified with the upper 2%?
IQ scores of at least the 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.
IQ scores of at least 130.81 are identified with the upper 2%.
Answer:
513.69
Step-by-step explanation:
^^^^
Subtract 748.25 by 234.56 and you get
You only need one of them:
(135 mile²) x (5,280 feet/mile)²
= (135 mile²) x (27,878,400 feet²/mile²)
= (135 x 27,878,400) mile² - feet² / mile²
= 3,763,584,000 feet²
The answer is the second option, or Ray BE is a bisector of angle ABE.
Answer: 122.5
======================================================
Explanation:
First thing to do is to find the perimeter of figure B. Add up all the sides and we get: 5+9+9+12 = 14+21 = 35.
The scale factor 7:2 means that if the perimeter of figure A was 7, then the perimeter of figure B would be 2. Or it could be 14 for A and 4 for B. And so on. The idea is that the two perimeters scale up or down together. This allows us to set up the proportion below in which we can solve for x
(perimeter of A)/(perimeter of B) = 7/2
x/35 = 7/2
x*2 = 35*7 .... cross multiply
2x = 245
2x/2 = 245/2 .... divide both sides by 2
x = 122.5
The perimeter of figure A is 122.5
