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3 years ago

Helpppppppppppppppppppppppppppppppppppppppppppppp

Mathematics

1 answer:

Aleksandr-060686 [28]3 years ago

3 0

Help with what im so confused

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Can someone help me , with math thanks

serious [3.7K]

Answer:

2+w greater than 5

Step-by-step explanation:

w=-3

3 0

3 years ago

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Guys, I need help with my Last year’s Hung Vuong Learning Centre Incorporated math homework package like immediately, I'll give

Ilia_Sergeevich [38]

Answer:

a) Cruz = 80000 + 35g + 25a

Gortan = 60000 + 20g + 18a

McKinnon = 100000 + 42g + 30a

b) total earnings = 240000 + 97g + 73a

c) $266,700

Step-by-step explanation:

g = bonus for goals

a = bonus for assists

a) Cruz = 80000 + 35g + 25a

Gortan = 60000 + 20g + 18a

McKinnon = 100000 + 42g + 30a

b) total earnings = 80000 + 35g + 25a + 60000 + 20g + 18a + 100000 + 42g + 30a

total earnings = 240000 + 97g + 73a

c) if g = 200 and a = 100

total earnings = 240000 + 97(200) + 73(100) = $266,700

7 0

3 years ago

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Evaluate the given algebraic expression for X=-2 and y = 3. ху 24 12 54 -24

Jobisdone [24]

Answer:

12 i think, bc 3 is bigger than 2, in apsolute number, so its 12

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4 years ago

What is the value of 20 - 6x3 +7

andrey2020 [161]

Answer:

Step-by-step explanation:

you must use PEMDAS:

1) Parentheses

2)Exponents ( you have no expeonents here

3) Multiply

4) Divide

5) Add

6) Subtract

solve in this order ^^

hope this helpsss

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3 years ago

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on a deposit of $4,000 that earns 8% compound interest compounded annually how much will you have after 2 years

NikAS [45]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$4000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=4000\left(1+\frac{0.08}{1}\right)^{1\cdot 2}\implies A=4000(1.08)^2\implies A=4665.6$

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4 years ago