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o-na [289]
3 years ago
13

The Des Plaines River Bridge is 2.1 km long. Engineers are considering re-lighting the bridge with a pole placed every 120 feet

of the bridge length starting from the south end. Each pole will support four light globes. How many globes will be required for the re-lighting project?.
Mathematics
1 answer:
ki77a [65]3 years ago
3 0
The amount of globes needed/required for the re-lightning project of the Des Plaines River Bridge is approximately 228. The equation for the answer is <span>2.1 km * 1mi/1.60934km * 5280 ft/mi = 6889.781ft /120ft = 57.41 poles,</span>57*4 = 228 bulbs.
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Solve x2 + 14x = −24 by completing the square.
Aleks04 [339]

Option A

The solution set of the equation is {-12, -2}

<h3><u>Solution:</u></h3>

Given equation is:

x^2 + 14x = -24

We have to find the solution set of this equation by completing the square

First, rearrange the equation so that only zero will be on the right side:

x^2 + 14x + 24 = 0 ----- eqn 1

<em><u>The general form of quadratic equation is:</u></em>

ax^2 + bx + c = 0 where a \neq 0

On comparing the given eqn 1 with general quadratic equation, we get

a = 1

b = 14

c = 24

In completing the square, we take half of coefficient of middle term "x" and then square it. Then we add it on both sides of the equation

So to complete the square, add (\frac{b}{2})^2 to both sides of the equation

x^2 + 14x + 24 + (\frac{14}{2})^2 = (\frac{14}{2})^2

x^2 + 14x + 24 + 7^2 = 7^2\\\\x^2 + 14x + 24 + 49 = 49

x^2 + 14x + 24 + 49 = 49\\\\x^2 + 14x + 49 = 49 - 24\\\\x^2 + 14x + 49 = 25\\\\(x + 7)(x + 7) = 25\\\\(x + 7)^2 = 25

Take square root on both sides

x + 7 = \sqrt{25}

x+7=\pm 5

Now make two equations

x + 7 = + 5 and x + 7 = -5

x = +5 - 7 = -2

x = -2

And,

x + 7 = -5

x = -5 - 7 = -12

x = -12

Therefore, the solution set of the equation is {-12, -2} and option A is correct

6 0
3 years ago
Read 2 more answers
Pls help me<br> 10 12 15 str 220 pls help me
ikadub [295]

Answer:

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Help me !! And show your work
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10d=40
10d/10=40/10
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C=2r
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