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2 years ago

(0,8) (-2,0). What is the equation of the linear graph shown?

Mathematics

1 answer:

Alex73 [517]2 years ago

6 0

Answer:

x value increases by 2 in the time it takes y value to increase by 8

8/2 = 4

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A snowmobile traveled 32 miles in 2 1/3 hours.

laila [671]

Answer:

13.7 mph

Step-by-step explanation:

• d = st

Given:

d = 32 miles
t = 2 1/3 hr = 7/3 hr

Find the rate s:

s = d/t
s = 32-7/3 = 32 x 3/7 = 96/7 = 13.7 mph (rounded)

5 0

2 years ago

Need to know how to graph this example y= -2x + 25. I know that y=mx+b. Just confused on how to get what they call plug in. Can

Artist 52 [7]

Here's an example
Y=5x + 10
if x is equal to 5 you would make it
Y=5(5)+10.
basically, just replace the x with what it's equal to.

7 0

3 years ago

In a recent poll, 44% of survey respondents said that, if they only had one child, they would prefer the child to be a boy.

viva [34]

Answer:

a) The probability that 71 of 150 will prefer boy child is 71/150 or 0.47

b) The result contradicts the poll actual percentage is 47.33% which is 3.33% more than the poll predicted

Step-by-step explanation:

If 71 out of 150 prefer boy child

The probability that the 71 will prefer boy child is

= 71/150

The actual percentage is

(71/150)*100%

= 47.33%

This contradicts the poll as this is more than the poll predicted. That means Less than 71 of 150 actually preferred boy child.

5 0

3 years ago

4x+4y=15. missing coordinate in the ordered pair (−5,?)

Black_prince [1.1K]

I domt get what you mean by coordinate pair could you explain plseas

6 0

3 years ago

Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the

Rama09 [41]

Question:

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s 2s 3s 4s

Answer:

It takes 2 seconds for object to hit the ground

Solution:

The given equation is:

$h(t) = -16t^2 + v_0t+h_0$

Initial velocity = 27 feet/sec

$h_0 = 10\ feet$

Therefore,

$h(t) = -16t^2 +27t+10$

At the point the object hits the ground, h(t) = 0

$-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0$

Solve by quadratic formula,

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125$

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0

3 years ago