Answer:
A (4-g)1.5
Step-by-step explanation:
hope this helps if you need a explanation just ask in the comments and I will.
Answer:
The ratio of the intensities is roughly 6:1.
Step-by-step explanation:
The intensity I() of an earthquake wave is given by:
<em>where P: is the power ans d: is the distance. </em>
Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:

<em>where I₁ = P/4πd₁², d₁=19 km, I₁ = P/4πd₂² and d₂=46 km </em>

Therefore, the ratio of the intensities is roughly 6:1.
I hope it helps you!
Answer:
4/5
Step-by-step explanation:
You look to where the line would meet a point on the graph ( you need 2) then you find rise over run or the y/x difference
Answer:
<u>8/3 or 2 2/3 gallons of paint</u>
Step-by-step explanation:
If 2/3 of paint covers 1/4 of the wall, you must multiply 2/3 by 4 to get 4/4 (the whole wall).
2/3 x 4 = 8/3 or 2 2/3
<em><u>Answer</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em><em><u> </u></em><em><u>opti</u></em><em><u>on</u></em><em><u> </u></em><em><u>3</u></em><em><u>r</u></em><em><u>d</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em><em><u> </u></em>
Step-by-step explanation:
∆FGE ~ ∆ JKL
i.e, Angle FGE = angle JKL = 63°
and angle GEF = angle KLJ = 29°
also, angle GFE = angle KJL = 88°
so, the ∆FGE ~ ∆ JKL by AA property of similarity !!
• not other options because if we take corresponding angle they are not equal
For eg. for ∆ EFG ~ ∆ JKL
the angle EFG must be equal to angle JKL to be similar !!
but they are not equal !!
so, they are not similar !!
and such ,all other options except 3rd is wrong !!