Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²
First posible triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=5 (5²=25)
13³=144 + 25
Answer:can be side lengths of a triangle
Second triangle:
hypotenuse=12.6 (12.6²=158.76)
leg₁=6.7 ( 6.7²=44.89)
leg₂=6.5 (6.5²=42.25)
leg₁²+leg₂²=44.89+42.25=87.14≠158.76
Answer: cannot be side lenghts of a triangle.
third triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=11 (11²=121)
leg₁²+leg₂²=144+121=265≠169
Answer: cannot be side lenghts of a triangle.
fourth triangle:
hypotenuse=13 (13²=169)
leg₁=6 ( 6²=36)
leg₂=4 (4²=16)
leg₁²+leg₁²=36+16=52≠169
Answer: cannot be side lenghts of a triangle.
So 1/2 is 5/10 and 2/5 is 4/10 common denonominator is 10 ( i think )
Answer:
B
Step-by-step explanation:
each time she sells 2 cards she gets $9 right?
so counting by 2's is the best route to go on and the only answer that displays that is answer B
Answer:
27
Step-by-step explanation:
angle adjacent to 163 = 27
x=27 by alternate angles equal principle.
" of " means multiply
2/3(27) = 54/3 = 18
2/5(20) = 40/5 = 8
so 2/5 of 20 is smaller
