The equation that represents this hanger is: 4w=25
The weight of one circle is: 6.25
<span>p=210e^(0.0069*20)
'e' is a mathematical constant equal to 2.718281828459
</span>
<span>0.0069*20 = .138
e^.138 =
</span>
<span>2.718281828459^.138 =
</span>
<span>
<span>
<span>
1.1479755503
</span>
</span>
</span>
210 * <span>1.1479755503 =
</span>
<span>
<span>
<span>
241.074865563
</span>
</span>
</span>
Answer: x=4
Steps: (I am assuming your question has a typo in it and by "c" you meant "x")
The rational expression equals zero

only when the numerator equals 0 (the denominator cannot ever be zero):

and that happens only for x=4
Answer:
Given:
In Rhombus QRST, diagonals QS and RT intersect at W and U∈QR and point V∈RT such that UV⊥QR. (shown in below diagram)
To prove: QW•UR =WT•UV
Proof:
In a rhombus diagonals bisect perpendicularly,
Thus, in QRST
QW≅WS, WR ≅ WT and m∠QWR=m∠QWT=m∠RWS=m∠TWS=90°.
In triangles QWR and UVR,
(Right angles)
(Common angles)
By AA similarity postulate,

The corresponding sides in similar triangles are in same proportion,


(∵ WR ≅ WT )
Hence, proved.