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2 years ago

Find a recursive rule for the nth term of the sequence. 5, 20, 80, 320, ...

Mathematics

1 answer:

Ira Lisetskai [31]2 years ago

7 0

Answer:

$a_1 = 5$

$a_n = 4a_{n - 1}$

Step-by-step explanation:

$a_1 = 5$

20/5 = 4

80/20 = 4

320/80 = 4

This a geometric sequence with r = 4.

$a_n = 4a_{n - 1}$

Answer:

$a_1 = 5$

$a_n = 4a_{n - 1}$

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Simplify completely''''

34kurt

Answer:

$\displaystyle \frac{2(x + 3)}{5x - 2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

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Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{2x^2 + 16x + 30}{5x^2 + 13x - 6}$

Step 2: Simplify

[Fraction] Factor numerator: $\displaystyle \frac{2(x + 3)(x + 5)}{5x^2 + 13x - 6}$
[Fraction] Factor denominator: $\displaystyle \frac{2(x + 3)(x + 5)}{(x + 3)(5x - 2)}$
[Fraction] Divide: $\displaystyle \frac{2(x + 3)}{5x - 2}$

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3 years ago

The Human Resources manager at a company records the length

luda_lava [24]

Answer:

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3 years ago

Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

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That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

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3 years ago

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Melissa has a collection of different colored hair bows. Some of the hair bows are big, and some of the hair bows are small. The

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Answer:

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Step-by-step explanation:

7/55 or 12.727272727273%

7 big and pink

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?= amount of bows

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7/55

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3 years ago

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3 years ago

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