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2 years ago

Match the following pair of angles with their respective definitions. Pls help

Mathematics

2 answers:

BigorU [14]2 years ago

8 0

Answer:

<3 and <7 = Corresponding angles

<2 and <7 = Alternate exterior angles

<4 and <5 = Alternate interior angles

<3 and <6 = Alternate interior angles

Try to learn these different angles so it's easier for you.

PolarNik [594]2 years ago

6 0

3,7 corresponding 2,7 exterior
4,5 & 3,6 interior

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Part A A high school athlete ran the 100 meter sprint in 13.245 seconds. Round the time to the nearest tenth.Part B Explain how

amid [387]

Answer:

t = 13.2 s

Step-by-step explanation:

Given that,

An athlete ran the 100 meter sprint in 13.245 seconds. We need to round off the time to the nearest tenth.

Here, t = 13.245 s

In order to round off to the nearest tenth, thousandths place and hundredth place gets eliminated.

So, t = 13.2 s

So, time is 13.2 seconds.

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3 years ago

2895÷229=<br> PLZ RIGHT WITH WHOLE NUMBER AND REMANDER<br> ---<br> R:

Eduardwww [97]

Answer:

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Step-by-step explanation:

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2 years ago

Which of the following sets of ordered pairs is a function?

Bumek [7]

I think B. Would be the answer

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3 years ago

For parts a and bâ, use technology to estimate the following. âa) The critical value of t for a 90â% confidence interval with df

rjkz [21]

Answer:

a) For the 90% confidence interval the value of $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

$t_{\alpha/2} =\pm 2.35$

b) For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

$t_{\alpha/2} =\pm 2.62$

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

Part a

For the 90% confidence interval the value of $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

$t_{\alpha/2} =\pm 2.35$

Part b

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

$t_{\alpha/2} =\pm 2.62$

3 0

3 years ago

I need help please, Its for today

Orlov [11]

Answer:

a) 1,2; 3.4

b) <1=<6, <6+<6+72=180, 2<6=108, <6=54.

<1=54

You can tell this by "these are parallel lines"

7 0

2 years ago