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3 years ago

The area of the base of a cylinder is equivalent to the base of a circle? A) True. B) False

Mathematics

1 answer:

gogolik [260]3 years ago

3 0

Answer:

Yes

Step-by-step explanation:

The base of both the cylinder and Circle are both circles.

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X + x + x = 54<br> What’s the answer for this

Oliga [24]

Answer:

x = 18

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

x+x+x=54

(x+x+x)=54(Combine Like Terms)

3x=54

Step 2: Divide both sides by 3.

3x 3 = 54

3 x=18

Answer:

x=18

8 0

3 years ago

Read 2 more answers

At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a

morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = $\dfrac{15}{120}=0.125$

As we know the poisson process, we get that

$P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda$

So, for exactly one car would be

P(n=1) is given by

$=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599$

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

$0.2599\times 18=4.6798$

We will find the traffic flow q such that

$P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr$

b. Estimate the percentage of time headways that will be 14 seconds or greater.

so, it becomes,

$P(h\geq 14)=e^{\frac{-qt}{3600}}\\\\P(h\geq 14)=e^{\frac{-415.88\times 14}{3600}}\\\\P(h\geq 14)=0.198\\\\P(h\geq 14)=19.8\%$

Hence, a) 4.6798, and b) 19.8%.

7 0

3 years ago

Two families went to the event. The first family bought two children's tickets and one adult ticket and paid a total of 8.2 euro

blagie [28]

Answer:

Step-by-step explanation:

step a system of two equations c = child ticket a = adult ticket

eq 1) 2c + 1a = 8.2 multiply by 2

eq 2) 3c + 2a = 14.1

I will multiply eq 1 times TWO and subtract eq 2 from eq 1a)

eq 1a) 4c + 2a = 16.4

eq 2) 3c + 2a = 14.1

subtract (4c - 3c) + (2a -2a) = 16.4 - 14.1

c + 0 = 2.3 euros for one child ticket

Now find the adult ticket price, plug 2.3 for c into eq 1)

eq 1) 2c + 1a = 8.2

eq 1) 2(2.3) + 1a = 8.2 solve for a

4.6 + a = 8.2 substract 4.6 from both sides

a = 8.2 - 4.6

= 3.6 euros for one adult ticket

double check using eq 2) we know c and a values

eq 2) 3c + 2a = 14.1

eq 2) 3(2.3) + 2(3.6) = 14.1

6.9 + 7.2 = 14.1

14.1 = 14.1

5 0

3 years ago

can someone explain it to me, i don't need the answer, i just need an detailed explanation of how they got the answer using the

zubka84 [21]

Answer:

Step-by-step explanation:

Good idea to review quadratic functions and the quadratic formula.

Quadratics have three coefficients: ax² + bx + c, and the "discriminant" is defined as b²-4ac. Please review these rules:

1) if the discriminant is +, the quadratic equation has two real, unequal roots.

2) if the disc. is 0, the equation has two real, equal root.

3) If the disc. is - , the equation has two complex roots.

Here a = 1, b = -3 and c = 4. Therefore the discriminant is (-3)²-4(1)(4), or

-7. Rule 3) applies: the equation has two complex roots, but no real ones. Thus we know that the graph does not cross the x-axis.

Graphing the given quadratic, x² - 3x + 4, using a dashed "line," is helpful. As you can see in the illustration of this graph, the graph neither touches nor crosses the x-axis. Thus, y = x² - 3x + 4 is greater than 0 for all x. The answer: All real numbers.

4 0

3 years ago

Find missing angleeeeeeeeeeeeeeeeeeeeeeee

dimulka [17.4K]

Answer:

C) 80

Step-by-step explanation:

triangles always add up to 180 degrees, so 80+20=100 the missing angle is 80 degrees

4 0

3 years ago

The area of the base of a cylinder is equivalent to the base of a circle? A) True. B) False​

The area of the base of a cylinder is equivalent to the base of a circle? A) True. B) False