All categories

3 years ago

Combining like terms

Mathematics

2 answers:

ololo11 [35]3 years ago

3 0

Like terms are where there variables are the same

Kay [80]3 years ago

3 0

We’re the variable are the same

You might be interested in

Can some one help please!!!!!!!

trapecia [35]

Answer:

yes it's easy

Step-by-step explanation:

y=-2x

it may help you to understand.

8 0

3 years ago

Mr. Lewis brought everyone in his class Bruster’s Ice Cream. The cost of the ice cream was $154.00. If he leaves a 18% tip, how

AVprozaik [17]

To find this answer multiply the cost of the ice cream by 18%/100, or .18

$154 x .18 = $27.72

3 0

3 years ago

Read 2 more answers

Need help ASAP midterm - 70 points

grin007 [14]

Answer:

I believe it is c

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

This morning, some dragons, horses, and chickens were playing in my backyard. I counted 15 heads, 50 legs, and 4 wings. How many

klasskru [66]

We are given

number of heads =15

we know that

any healthy dragon has three heads

horse has 1 head

chicken has 1 head

Let's assume

number of dragons is x

number of horses is y

number of chickens is z

so, we will get

first equation:

$3x+y+z=15$

number of legs =50

any healthy dragon has four legs

chicken has 2 legs

horse has four legs

so, we can get second equation as

$4x+4y+2z=50$

we can simplify it

$2(2x+2y+z)=50$

$2x+2y+z=25$

now, we can find third equation

dragon has two wings

horse has no wings

chicken has two wings

so, we will get third equations as

$2x+0y+2z=4$

now, we can simplify it

$2x+2z=4$

$2(x+z)=4$

$x+z=2$

so, we will get system of equations as

$3x+y+z=15$

$2x+2y+z=25$

$x+z=2$

now, we can use substitution

We can find for z from third equation

$z=2-x$

we can plug this in first equation

$3x+y+2-x=15$

now, we can solve for y

$2x+y+2=15$

$y=13-2x$

now, we can plug this z and y into second equation

$2x+2(13-2x)+2-x=25$

now, we can solve for x

$x-4x+26=23$

$-3x=-3$

$x=1$

now, we can find y and z

$y=13-2x$

we can plug x=1

$y=13-2*1$

$y=11$

$z=2-x$

we can plug x=1

$z=2-1$

$z=1$

Hence ,

number of dragons is 1

number of horses is 11

number of chicken is 1............Answer

7 0

3 years ago

41. Assuming that a man can complete the work alone in x days, his work in four days would be: a) b) X X C d) 4x x 42. If a man

Schach [20]

Percentage and ratio word problems require understanding of the relationship between variables from which the question is formed

The options that give the correct values of the duration of the work are;

$41. \ c) \ \dfrac{4}{x}$

$42. \ d) \ \dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

43. a) 35 days

44. c) 21·a + 28·b = 1

45. c) (42, 56)

Reasons:

41. Number of days it takes a man to complete the work alone = x days

Therefore;

$The \ work \ done \ by \ the \ man \ in \ one \ day = \dfrac{1}{x}$

$The \ work \ done \ in \ four \ days \ by\ the \ man = 4 \times \dfrac{1}{x} = \dfrac{4}{x}$

The correct option is $c) \ \dfrac{4}{x}$

42. Number of days it takes a man to complete the work alone = x days

$Work \ done \ by \ a\ man \ in \ one \ day = \dfrac{1}{x}$

$Work \ done \ by \ four \ men \ in \ one \ day = \dfrac{4}{x}$

Number of days it takes a boy to complete the work alone = y days

$Work \ done \ by \ a \ boy \ in \ one \ day = \dfrac{1}{x}$

$Work \ done \ by \ six \ boys \ in \ one \ day = \dfrac{6}{y}$

4 men and 6 boys work for 5 days to complete the work

Therefore, work done by 4 men and 6 boys in 1 day is therefore;

$\dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

The correct option is therefore;

$d) \ \dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

43. As per the case study, we have;

Case 1

$\dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

Which gives;

$\dfrac{6\cdot x + 4\cdot y}{y \cdot x} = \dfrac{1}{5}$

30·x + 20·y = y·x

Case 2

$\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$

Which gives;

$\dfrac{4\cdot x + 3\cdot y}{y \cdot x} = \dfrac{1}{7}$

28·x + 21·y = y·x

Therefore;

30·x + 20·y = 28·x + 21·y

∴ 2·x = y

Plugging in the value of y = 2·x, in Case 1 gives;

$\dfrac{4}{x} + \dfrac{6}{2 \cdot x} = \dfrac{1}{5}$

$\dfrac{2 \times 4 + 6}{2 \times x} = \dfrac{14}{2 \times x} =\dfrac{7}{x} = \dfrac{1}{5}$

7 × 5 = x

x = 7 × 5 = 35

The number of days, x, it takes a man to complete the work alone, is given by option; a) 35 days

44. For the equation $\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$ , if $a = \dfrac{1}{x}$ , and $b = \dfrac{1}{y}$ , we have;

$3 \cdot a+ 4\cdot y = \dfrac{1}{7}$

21·a + 28·y = 1

The correct option is option C. 21·a + 28·b = 1

45. A solution to the equation $\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$ , is given by the values of x, and y, that gives;

$\dfrac{1}{14} + \dfrac{1}{14} = \dfrac{1}{7}$

We have;

3 × 14 = 42

4 × 14 = 56

Therefore, a solution to the equation is (42, 56)

The correct option is $c) \ \underline{ (42, \ 56)}$

Learn more here:

brainly.com/question/11825953

brainly.com/question/14626596

brainly.com/question/15573651

3 0

2 years ago