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lesya [120]
3 years ago
5

Distribute and combine like terms 3(2x + 4) + 2x - 4

Mathematics
2 answers:
Sphinxa [80]3 years ago
4 0
The answer to your question is
8x + 8
irga5000 [103]3 years ago
4 0

 

3(2x + 4) + 2x - 4

6x + 12 + 2x - 4

If you wanted to only combine, the answer would be: 8x - 8

If you wanted to solve for x, the answer would be x = -1


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PLEASE HELP!!
aliya0001 [1]

Ik this is late, but people who are looking for the answer can see this.

Answer:

an =1/3*6^n-1

Step-by-step explanation:

You should plug in 2 for n in each equation, which, the correct one should give you 2. Then, to make sure, you plug in 3 in the equations that gave you 2.

Example:

an = 1/3 * 6 ^n-1

Plug in 2.

an = 1/3 * 6 ^2-1

an = 1/3 * 6 ^1

1/3 * 6 = 2

Step 2.

an = 1/3 * 6 ^3-1

an = 1/3 * 6 ^2

1/3 * 36 = 12

Hope this helps.

4 0
3 years ago
Z=b+ m/a, solve for a
Tpy6a [65]
You can not solve for a as all of the numbers are unknown
7 0
3 years ago
WORTH 99 POINTS!
Ksivusya [100]
The general formula for the lateral surface area of a regular pyramid is:
A= \frac{1}{2} *p*l
Where:
p=perimeter of a base
l=slant height

a.
a=3ft
l=4ft
p=5*a=5*3=15ft
A= \frac{1}{2} *15*4=30 ft^{2}

b.
a=2.5ft
l=4ft
p=6*a=6*2.5=15ft
A= \frac{1}{2} *15*4=30 ft^{2}

c.
a=1.9ft
l=4ft
p=8*a=8*1.9=15.2ft
A= \frac{1}{2} *15.2*4=30.4 ft^{2}

d.
Based on a lateral surface area the blue umbrella is best choice. But, the best umbrella overall is the one with the greatest base area. General formula for regular polygon is:
A= \frac{1}{4} *n* a^{2}*cot( \frac{180}{n} )

For pentagon:
A=15.48ft^2
For hexagon:
A=16.24ft^2
For octagon:
A=17.43ft^2
Blue umbrella is still best choice.
8 0
3 years ago
Read 2 more answers
Picture is shown !
Anarel [89]
It should be 17, 26, 35, 44, 53
5 0
3 years ago
Read 2 more answers
M1 Matrix is:
harkovskaia [24]

Answer:

(a)First Row, First Column =1

(b)First Row, second Column =0

(c)Second Row, First Column =0

(d)Second Row, second Column =1

Step-by-step explanation:

Given matrix M=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)

The Inverse of a 2X2 matrix

A=\left(\begin{array}{ccc}a&b\\c&d\end{array}\right)

can be found using the following:

A^{-1}=\dfrac{1}{ad-bc} \left(\begin{array}{ccc}d&-b\\-c&a\end{array}\right)

Therefore:

M^{-1}=\dfrac{1}{(5*-5)-(3*-8)} \left(\begin{array}{ccc}5&-3\\8&-5\end{array}\right)\\=-1\left(\begin{array}{ccc}5&-3\\8&-5\end{array}\right)\\=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)

Next, we find the product M^{-1}M

M^{-1}M=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)\\=\left(\begin{array}{ccc}-5*-5+3*-8&-5*3+3*5\\-8*-5+5*-8&-8*3+5*5\end{array}\right)\\=\left(\begin{array}{ccc}1&0\\0&1\end{array}\right)

Therefore:

(a)First Row, First Column =1

(b)First Row, second Column =0

(c)Second Row, First Column =0

(d)Second Row, second Column =1

NOTE: The multiplication of a matrix and its inverse always gives the identity matrix as seen above,

7 0
3 years ago
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