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blsea [12.9K]
4 years ago
10

39.54 divided by 3 please.

Mathematics
2 answers:
jeka57 [31]4 years ago
5 0

Answer: 13.18

Step-by-step explanation:

SOVA2 [1]4 years ago
4 0

Answer: 13.18

Step-by-step explanation: But if rounded to the nearest tenth its 13.2

hope that helped

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Find equations of the tangent plane and the normal line to the given surface at the specified point. x + y + z = 8exyz, (0, 0, 8
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Let f(x,y,z)=x+y+z-8e^{xyz}. The tangent plane to the surface at (0, 0, 8) is

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(1,1,1)\cdot(x,y,z-8)=0\implies x+y+(z-8)=0\implies x+y+z=8

The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by t, then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation

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To learn more about quadratic equations refer to:

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