5. a^2 + b^2 = c^2...where a and b are the legs and c is the hypotenuse
7^2 + 10^2 = c^2
49 + 100 =c^2
149 = c^2....take square root of both sides, eliminating the ^2
sq rt 149 = c
12.21 = c.....so the approximate length of 3rd side is 12 m
6. x = number of books bought
7. m < 2 + m < 8 = 180
8. 1000 = 400 + 24x
1000 - 400 = 24x
600 = 24x
600/24 = x
25 = x <=== 25 months he will have spent $ 1000
I’m assuming ‘dives further’ means to go directly down
the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.
let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)
then this become a simple trig problem:
A)
Let O be the position of of the ship, and C be the original position of the submarine.
therefore, not considering direction
|OC| = 1.78km = 1780m
|CA| = 45m
these are the adjacent and opposite sides of a right angled triangle.
But tan($) = opp/adj = |CA|/|OC| = 45/1780
therefore $ = arctan(45/1780) which is roughly 1.45 degrees,
B)
similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m
tan(¥) = 107/1780
¥ = arctan(107/1780) which is roughly 3.44 degrees
The solution to this equation is in the picture i’ve put below!
The correct answer is B. cm3
This is saying "centimeters cubed", and is true because you are multiplying 3 dimensions of centimeters, width*length*height, to get the answer. Thus, you are multiplying the numbers <em>and </em>the units. 30*30*25 and cm*cm*cm
