To find the x-intercepts algebraically, we let y = 0 y=0 y=0 in the equation and then solve for values of x. In the same manner, to find for y-intercepts algebraically, we let x = 0 x=0 x=0 in the equation and then solve for y.
A. solve for 1 variable
let's solve for x in 2nd equation
add 2y to both sides
x=2y+4
sub 2y+4 for x in other equation
3(2y+4)+y=5
6y+12+y=5
7y+12=5
minu12 both sides
7y=-7
divide 7
y=-1
sub back
x=2y+4
x=2(-1)+4
x=-2+4
x=2
(2,-1)
B. eliminate
eliminate y's
multiply first equation by 2 and add to first
6x+2y=10
<u>x-2y=4 +</u>
7x+0y=14
7x=14
divide by 7
x=2
sub back
x-2y=4
2-2y=4
minus 2
-2y=2
divide -2
y=-1
(2,-1)
(2,-1) is answer
I hope this helps you
-4x-7+5x+2
x-5
Here is how you solve...
Q= 3a+5ac
take out the common variable.
Q= a(3+5c)
get A by its self so divide each side by (3+5c).
Q/a(3+5c)= a(3+5c)/(3+5c)
Q/a(3+5c)=A
So your answer is A= Q/a(3+5c)
hope that helped.
The probability of drawing a spade is 13/52 = 1/4
Because every hand has 13 cards and there is 52 cards in a deck
The probability of drawing a 7 is 4/52 or 1/13
Because there are seven 7 cards in a deck and 52 cards.
