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AnnyKZ [126]
3 years ago
7

A student is randomly selected from a class of 32 students. What is the probability that the selected student is a boy if there

are 20 girls in the class
Mathematics
1 answer:
NikAS [45]3 years ago
6 0

Answer:

Probability of selecting a boy will be: Number of boys/Total students= 12/32= 0.375

Step-by-step explanation:

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9–5(x+4)=3(2–x) help!!!!!1
netineya [11]

Answer:

-17/2 =x

Step-by-step explanation:

9–5(x+4)=3(2–x)

Distribute

9 - 5x - 20 = 6 -3x

Combine like terms

-5x-11 = 6-3x

Add 5x to each side

-5x-11 +5x = 6-3x+5x

-11 = 6+2x

Subtract 6 from each side

-11-6 = 6+2x-6

-17 = 2x

Divide by 2

-17/2 = 2x/2

-17/2 =x

3 0
3 years ago
Read 2 more answers
ABC Computers sold 30tablets. this week. their.goal is 33% more next. week Graph a inequality that represents their goal.
Grace [21]
Next week they will want to sell 40 tablets
8 0
3 years ago
How many 1 2/3 are in 1 1/6​
Flura [38]

Answer:

7/10

Step-by-step explanation:

To find how many of x are y, you solve <em>y/x</em>.

With our numbers, we have <em>7/6 ÷ 5/3</em>.

We can turn that into <em>7/6 × 3/5</em> = <em>21/30</em> = 7/10.

5 0
3 years ago
Rick was given a 15% tip waiting on a table of customers who ordered $60.00 in food and drinks. How much did Rick earn in tips f
Nata [24]

Answer:

$9

Step-by-step explanation:

15% of 60 is 9

thus, he earned $9

8 0
3 years ago
In the year 2005 , a total of 750 fish were introduced into a manmade lake . The fish population was expected to grow at a rate
xxTIMURxx [149]

Answer:

The fish population will be in 2050 = 27,123

Step-by-step explanation:

Given,

In 2005, the total number of fish were introduced (fish population), PV = 750

The growth rate, i = 8.3% = 0.083

The difference between 2050 and 2005 is (2050 - 2005), n = 45 years

We need to solve this problem with the help of future value of compounding. We know, FV = PV (1+i)^n, where, PV = present value, i = interest rate, n = period.

Therefore, the fish population will be in 2050 = 750 x (1 + 0.083)^45

The fish population will be in 2050 = 27,123.26

2050 fish population = 27,123 (Nearest to whole number).

3 0
3 years ago
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