Answer:
4:3 would be the ratio in its simplified form.
Answer:
If you call the smaller integer "x" and the greater integer "y", then:
x+y=3x-11 The sum of the two is 11 less than 3 times the smaller
y=x+1 Because they are consecutive, the greater must be 1 more than the smaller
Then you can solve for x:
x+(x+1)=3x-11 Substitute x+1 for y
2x+1=3x-11 Combine like terms
2x+12=3x Add 11 to both sides
12=x Subtract 2x from both sides
The smaller integer is 12, thus the greater integer is 1 more or 13.
Check:
12+13=3(12)-11
25=36-11
25=25 Yes, so the integers are 12 and 13
Step-by-step explanation:
thats pretty much it
2.2 x 5.00= 11
Lowest sig figs is 2
Answer:
D. (-2,0)
Step-by-step explanation:
The points in the darkest gray are any of the solutions. So the only point that is in there is D (-2,0)
