Question

5

Answer 1

Answer:

The length of the arc is 6.28 inches

Step-by-step explanation:

Given

$\theta = 60$

Required

Length of the arc

This is calculated as:

$L = \frac{\theta}{360} * 2\pi r$

So, we have:

$L = \frac{60}{360} * 2 * \frac{22}{7} * 6$

$L = \frac{15840}{2520}$

$L = 6.28in$