Answer:
,k
Step-by-step explanation:
n
To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer:
Undefined slope.
Step-by-step explanation:
The formula should be y2 - y1 over x2 - x1
Points ( 20,-16 ) and ( 19, -16 )
So ( -16 - ( -16 ) ) over ( 19 - 20 )
0 over -1
The slope is 0. Undefined.
x + 1/2 = 3/4
set denominators equal:
x + 2/4 = 3/4
-2/4 for both sides:
x = 1/4
there you go! hope this helps!
