Answer:
Long wings: 0
Short wings: 100
Step-by-step explanation:
Genotype of the flies: ww
The cross will yield the genotype ww and the flies will express the recessive phenotype which is short wings.
The probability for long wings will be 0 as there is no dominant allele present. The probability for short wings will be 100 as all the flies will have short wings.
Hope that helps.
_award brainliest if helped!
so 102% = 30396
100% (original) = 30396/102*100 =29800
Her salary was $29800 before the rise
Answer:
A) 6Gn + 12 (or 6n+12, if that’s what you meant)
B) 4p²+9p
C) 5r²+20r
Step-by-step explanation:
A. If you meant 6(n+2)...
Multiply 6 by n and also 6 by 2:
6n + 12
B. Multiply p by 4p and also p by 9
4p²+9p
C. Multiply 5r by r and also 5r by 4
5r²+20r
Hope this helped!
Answer:
Below in bold.
Step-by-step explanation:
A.This is the number of combinations of 6 from 15
= 15C6
= 15! / (15-6)! 6!
= 5,005 ways.
B. This is the number of permutaions of 6 from 15:
= 15! / (15-6)!
= 3,603,600 ways.
Answer:
23.52 miles
Step-by-step explanation:
Let us find the number of miles that they would have run.
Kana starts at 9:35 a.m. and runs at an average rate of 7 mph.
Let the time she has spent so far be t.
Speed is given as:
s = d / t
where d = distance and t = time
=> d = s * t
Therefore, for Kana:
d = 7 * t = 7t _____________(1)
Ji-Hun starts at 10:00 am (25 minutes after Hannah) and runs at an average rate of 8 mph.
25 minutes = 25/60 hour = 0.42 hour
So, his time (compared to Kana's) is t - 0.42.
therefore, for Ji-Hun:
d = 8 * (t - 0.42)
=> d = 8t - 3.36 ____________(2)
Equating (1) and (2):
7t = 8t - 3.36
=> 8t - 7t = 3.36
t = 3.36 hours
Therefore, let us find d:
d = 7 * 3.36 = 23.52 miles
So, Ji-Hun will catch up to Kana after 23.52 miles.
