We can solve this problem by referring to the standard
probability distribution tables for z.
We are required to find for the number of samples given the
proportion (P = 5% = 0.05) and confidence level of 95%. This would give a value
of z equivalent to:
z = 1.96
Since the problem states that it should be within the true
proportion then p = 0.5
Now we can find for the sample size using the formula:
n = (z^2) p q /E^2
where,
<span> p = 0.5</span>
q = 1 – p = 0.5
E = estimate of 5% = 0.05
Substituting:
n = (1.96^2) 0.5 * 0.5 / 0.05^2
n = 384.16
<span>Around 385students are required.</span>
Step-by-step explanation:
f/p = p(1+i)^n
p= 2500
i=0.03 =3%
n=4
2500(1 + 0.03)^4
Answer:
x=-24 is the correct answer
Answer:
5 i think
Step-by-step explanation:
what your asking is 5x5? so 25
