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Kazeer [188]
3 years ago
14

The Quality Control Department employs five technicians during the day shift. Listed below is the number of times each technicia

n instructed the production foreman to shut down the manufacturing process last week.
Technician Shutdowns
Taylor 2
Hurley 1
Gupta 3
Rousche 5
Huang 4
A. How many samples, without replacement, of size two are possible?
B. Compute the mean of the sample means and compare it to the population mean.
C. The mean of the sample means is_____.
D. The population mean is_____.
E. Both means are:_____.
a. not equal
b. equal.
Mathematics
1 answer:
natka813 [3]3 years ago
4 0

Answer:

it is a

Step-by-step explanation:

i dont realy like its hard for me to explain

You might be interested in
Make a list of 5 numbers with a mean of 12 and a mode of 15. <br><br> Explain if you can
mart [117]

The mean is the average value of the numbers given in the series

The mode is the number that is appears more than any other number given in the series

Step-by-step explanation:

Given challenge is make a list of 5 numbers

The list of 5 number is = 8,10,12,15,15

Mean value = (8+10+12+15+15)/5 =60/5 = 12

so required mean is 12 has been computed

Mode = 15 ( the number 12 is appeared in two times 8,10,12,15,15)

Final answer

The required numbers are = 8,10,12,15,15

6 0
4 years ago
Refer to Exercise 3.122. If it takes approximately ten minutes to serve each customer, find the mean and variance of the total s
garri49 [273]

Answer

a. The expected total service time for customers = 70 minutes

b. The variance for the total service time = 700 minutes

c. It is not likely that the total service time will exceed 2.5 hours

Step-by-step explanation:

This question is incomplete. I will give the complete version below and proceed with my solution.

Refer to Exercise 3.122. If it takes approximately ten minutes to serve each customer, find the mean and variance of the total service time for customers arriving during a 1-hour period. (Assume that a sufficient number of servers are available so that no customer must wait for service.) Is it likely that the total service time will exceed 2.5 hours?

Reference

Customers arrive at a checkout counter in a department store according to a Poisson distribution at an average of seven per hour.

From the information supplied, we denote that

X= Customers that arrive within the hour

and since X follows a Poisson distribution with mean \alpha = 7

Therefore,

E(X)= 7

& V(X)=7

Let Y = the total service time for customers arriving during the 1 hour period.

Now, since it takes approximately ten minutes to serve each customer,

Y=10X

For a random variable X and a constant c,

E(cX)=cE(X)\\V(cX)=c^2V(X)

Thus,

E(Y)=E(10X)=10E(X)=10*7=70\\V(Y)=V(10X)=100V(X)=100*7=700

Therefore the expected total service time for customers = 70 minutes

and the variance for serving time = 700 minutes

Also, the probability of the distribution Y is,

p_Y(y)=p_x(\frac{y}{10} )\frac{dx}{dy} =\frac{\alpha^{\frac{y}{10} } }{(\frac{y}{10})! }e^{-\alpha } \frac{1}{10}\\ =\frac{7^{\frac{y}{10} } }{(\frac{y}{10})! }e^{-7 } \frac{1}{10}

So the probability that the total service time exceeds 2.5 hrs or 150 minutes is,

P(Y>150)=\sum^{\infty}_{k=150} {p_Y} (k) =\sum^{\infty}_{k=150} \frac{7^{\frac{k}{10} }}{(\frac{k}{10})! }.e^{-7}  .\frac{1}{10}  \\=\frac{7^{\frac{150}{10} }}{(\frac{150}{10})! } .e^{-7}.\frac{1}{10} =0.002

0.002 is small enough, and the function \frac{7^{\frac{k}{10} }}{(\frac{k}{10} )!} .e^{-7}.\frac{1}{10}  gets even smaller when k increases. Hence the probability that the total service time exceeds 2.5 hours is not likely to happen.

3 0
3 years ago
If 20 squirrels can eat a bushel of corn in 10 hours, how many squirrels can eat a bushel of corn in 2 hours?
omeli [17]
So if 20 squirrels can eat a bushel of corn in 10 hours that means that 2 it needs 2 squirrels per hour.

So the answer would be 4 squirrels, hope this helps!
7 0
4 years ago
Read 2 more answers
Jerome works as a waiter. He earns $80 each weekend plus 15% in tips on meals served. Jerome served $725 worth of meals last wee
gulaghasi [49]

Answer:

well you would need to look at how much he gets a weekend, and then worry anout the tips.

Step-by-step explanation:

He gets paid $80 each weekend, and a 15% with tips.

you would need to figure out the tips, by taking the $725 and timesing it by .15 for the percent.

which would be 108.75

you would now take 108.75 and add 80 to get what he made that weekend.

108.75+80 = 188.75 dollars

5 0
3 years ago
Suppose that the regression equation y = 16.99 + 0.32 x1 + 0.41 x2 + 5.31 x3 predicts an adult’s height (y) given the individual
umka21 [38]

Answer:

Step-by-step explanation:

It is given that the regression equation

y = 16.99 + 0.32 x_1 + 0.41 x_2 + 5.31 x_3

predicts an adult’s height (y) given the individual’s mother’s height (x1), his or her father’s height (x2), and whether the individual is male (x3 = 1) or female (x3 = 0).

The coefficient of x1 = 0.32 represents the increase in height of the child due to one inch increase in mother.

Similarly coefficient of x2 = 0.42 represents the increase in height of the child due to one inch increase in father.

and coefficient of x3 = 5.31 represents the increase in height of the child due to being a male than a female.

8 0
3 years ago
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