2qt= ?ml round to nearest hundredths

Oro's book club was offering a special on books this month. He bought 5 for $0.98 each and then a regular book for $19.29. His t

Scrat [10]

5×.98 is 4.90 then add 19.29 and add 14.25. this equals $38.44 hope this helps.

8 0

2 years ago

Read 2 more answers

Is DEF a right triangle? True or false

umka2103 [35]

Short answer = false
Remark
If it is a right triangle, it will obey the Pythagorean Equation. a^2 + b^2 = c^2. Let's see if it does.

Equation
a^2 + b^2= c^2
c must be the longest line. (Hypotenuse)

Givens
a = 24
b = 17
c = 40

Sub and Solve
a^2 + b^2 = c^2
17^2 + 24^2 = c^2 [We'll see if this comes out to 40]

289 + 576 = c^2
865 = c^2 which is no where near what 40^2 equals. 40^2 = 1600

Short answer False

Square root of 865 = (865)^1/2 = 29.4

5 0

3 years ago

Hey guys, I need help with these questions. I need them done by today! Please, help :( There are 4 questions or more I think, I

Orlov [11]

Answer:

Step-by-step explanation:

Domain x^2 - 9 {Solution: - infinity < x < infinity}

Interval notation (- infinity, infinity)

Range of x^2 - 9 (Solution: f(x) is greater than or equal to - 9)

Interval notation (-9, infinity)

Axis interception points of x^2 - 9:

X- intercepts (3, 0) (-3, 0)

Y-intercepts (0, -9)

Vertex of x^2 - 9: Minimum (0, -9)

Solve for f:

f (x) = x^2 - 9

Step 1: Divide both sides by x.

fx / x = x^2 - 9 / x

f = x^2 - 9 / x

Answer:

f = x^2 - 9 / x

8 0

1 year ago

An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 75 type K batteries and a sample of 46

lorasvet [3.4K]

The decision rule for rejecting the null hypothesis, considering the t-distribution, is of:

|t| < 1.9801 -> do not reject the null hypothesis.

|t| > 1.9801 -> reject the null hypothesis.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is not enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means is of zero, hence:

$H_0: \mu_1 - \mu_2 = 0$

At the alternative hypothesis, it is tested if there is enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means different of zero, hence:

$H_1: \mu_1 - \mu_2 \neq 0$