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AleksAgata [21]
3 years ago
12

A letter to Europe from the United States cost $.94 to mail. A letter mailed within the United States cost $.44. Nancy mailed fi

ve letters for $3.70, some to Europe and some to the United States. How many letters did she send to Europe. Explain.
Mathematics
1 answer:
frosja888 [35]3 years ago
7 0

Answer:

3

Step-by-step explanation: i used my calculator

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What is the value of x.?
Strike441 [17]

Answer:

above is the answer to the question

7 0
2 years ago
Mr.O'Connor had $90 to spend at a football game. He spent 31/45 on his ticket. Then, he spent 3/7 of his remaining money at the
Alexxx [7]

Answer:

no

Step-by-step explanation:

he starts with 90 bucks to find what the fraction represents you can multiply it by 2 to get an equal denominator of 90 then subtract 90-62 that'll give you 28 then it says he spent 3/7 so you do the same thing get an equal denominator by multiplying by 4 and get 28 and as they say whatever you do to the denominator is done to the numerator so 3 times 4 is 12 then you do 28-12 and you gets 16 which isn't enough to buy the hat. :)

7 0
3 years ago
The total length of 3 pipes is 24 inches. The middle-sized pipe is 6 inches longer than the smallest. The largest is twice as lo
Flauer [41]

Answer:

18

Step-by-step explanation:

let the be x

if the middle sized pipe is 6 inches longer than the smallest.

so 24 subtract from 6=18

5 0
3 years ago
Bob and Anna are planning to meet for lunch at Sally's Restaurant, but they forgot to schedule a time. Bob and Anna are each goi
Viktor [21]

Answer:

The expected cost is $8.75

<em></em>

Step-by-step explanation:

Given

Time = \{1pm, 2pm, 3pm, 4pm\}

C_1 = \$5 --- If Bob and Anna meet

C_2 = \$10 --- If Bob and Anna do not meet

Required

The expected cost of  Bob's meal

First, we list out all possible time both Bob and Anna can select

We have:

(Bob,Anna) = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4),(4,1),(4,2),(4,3),(4,4)\}

n(Bob, Anna) = 16

The outcome of them meeting at the same time is:

Same\ Time = \{(1,1),(2,2),(3,3),(4,4)\}

n(Same\ Time) = 4

The probability of them meeting at the same time is:

Pr(Same\ Time)  = \frac{n(Same\ Time)}{n(Bob,Anna)}

Pr(Same\ Time)  = \frac{4}{16}

Pr(Same\ Time)  = \frac{1}{4}

The outcome of them not meeting:

Different = \(Bob,Anna) = \{(1,2),(1,3),(1,4),(2,1),(2,3),(2,4),(3,1),(3,2)

,(3,4),(4,1),(4,2),(4,3)\}

n(Different) = 12

The probability of them meeting at the same time is:

Pr(Different)  = \frac{n(Different)}{n(Bob,Anna)}

Pr(Different)  = \frac{12}{16}

Pr(Different)  = \frac{3}{4}

The expected cost is then calculated as:

Expected = C_1 * P(Same) + C_2 * P(Different)

Expected = \$5 * \frac{1}{4} + \$10 * \frac{3}{4}

Expected = \frac{\$5}{4} + \frac{\$30}{4}

Take LCM

Expected = \frac{\$5+\$30}{4}

Expected = \frac{\$35}{4}

Expected = \$8.75

<em>The expected cost is $8.75</em>

4 0
3 years ago
Jose has determined he needs to have $800,000 for retirement in 30 years. His account earns 6% interest.
bija089 [108]
A. $285,714.29/360 = $793.65
B. $285,714.29
C. $800,000-285,714.29 = $514,285.71

A. P/T(12)
B. P = A/(1+RT)
C. I = PRT or I = A-P

Answer:
P = $285,714.29

Equation:
P = A / (1 + rt)

Calculation:
First, converting R percent to r a decimal
r = R/100 = 6%/100 = 0.06 per year.

Solving our equation:
P = 800000 / ( 1 + (0.06 × 30)) = 285714.28571429
P = $285,714.29

The principal investment required to get a total amount, principal plus interest, of $800,000.00 from simple interest at a rate of 6% per year for 30 years is $285,714.29.
4 0
3 years ago
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