All categories

3 years ago

Evaluate the expression 5c - 2 = when c = 3 HELPPP quick

Mathematics

2 answers:

Ugo [173]3 years ago

8 0

Answer:

Step-by-step explanation:

Substitute 3 into c --> 5(3)-2 = 15-2 = 13

Juli2301 [7.4K]3 years ago

4 0

Answer:

Step-by-step explanation:

c=3 soOOo

5x3=15

15-2=13

You might be interested in

Maggie graphed the image of a 90 counterclockwise rotation about vertex A of . Coordinates B and C of are (2, 6) and (4, 3) and

Lemur [1.5K]

Answer:

A(2,2)

Step-by-step explanation:

Let the vertex A has coordinates $(x_A,y_A)$

Vectors AB and AB' are perpendicular, then

$\overrightarrow {AB}=(2-x_A,6-y_A)\\ \\\overrightarrow {AB'}=(-2-x_A,2-y_A)\\ \\\overrightarrow {AB}\perp\overrightarrow {AB'}\Rightarrow \overrightarrow {AB}\cdot \overrightarrow {AB'}=0\Rightarrow (2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0$

Vectors AC and AC' are perpendicular, then

$\overrightarrow {AC}=(4-x_A,3-y_A)\\ \\\overrightarrow {AC'}=(1-x_A,4-y_A)\\ \\\overrightarrow {AC}\perp\overrightarrow {AC'}\Rightarrow \overrightarrow {AC}\cdot \overrightarrow {AC'}=0\Rightarrow (4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0$

Now, solve the system of two equations:

$\left\{\begin{array}{l}(2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0\\ \\(4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0\end{array}\right.\\ \\\left\{\begin{array}{l}-4-2x_A+2x_A+x_A^2+12-6y_A-2y_A+y^2_A=0\\ \\4-4x_A-x_A+x_A^2+12-3y_A-4y_A+y_A^2=0\end{array}\right.\\ \\\left\{\begin{array}{l}x_A^2+y_A^2-8y_A+8=0\\ \\x_A^2+y_A^2-5x_A-7y_A+16=0\end{array}\right.$

Subtract these two equations:

$5x_A-y_A-8=0\Rightarrow y_A=5x_A-8$

Substitute it into the first equation:

$x_A^2+(5x_A-8)^2-8(5x_A-8)+8=0\\ \\x_A^2+25x_A^2-80x_A+64-40x_A+64+8=0\\ \\26x_A^2-120x_A+136=0\\ \\13x_A^2-60x_A+68=0\\ \\D=(-60)^2-4\cdot 13\cdot 68=3600-3536=64\\ \\x_{A_{1,2}}=\dfrac{60\pm8}{2\cdot 13}=\dfrac{34}{13},2$

Then

$y_{A_{1,2}}=5\cdot \dfrac{34}{13}-8 \text{ or } 5\cdot 2-8\\ \\=\dfrac{66}{13}\text{ or } 2$

Rotation by 90° counterclockwise about A(2,2) gives image points B' and C' (see attached diagram)

8 0

3 years ago

What are the factors of the quadratic function graphed below?

natulia [17]

Answer:

Step-by-step explanation:

The zeros of the quadratic occur at x = 0 and x = 6

Thus the factors are x and x - 6

4 0

3 years ago

Find cos theta if sin theta=3/4 and theta lies in quadrant 2

GaryK [48]

By the Pythagorean theorem, the missing side is -sqrt7. The definition of sin is side opposite over hypotenuse, so go into Q2 and make an angle and label the side opposite the angle with a 3 and the hypotenuse a 4. The other leg is -sqrt7 cuz x is negative in Q2. The cosine of an angle is the side adjacent over the hypotenuse, so the cos then is -sqrt7/4

7 0

3 years ago

Joe went to the hobby shop and bought 2 sport cars at %8.95 each and some paints.If he spent a total of %23.65,What was the coas

sweet-ann [11.9K]

I'm assuming that % means $:

8.95*2 = 17.9

23.65 - 17.9 = 5.74

The cost of the paint was $5.74

7 0

3 years ago

Cool Scoops ice cream shop offers 42 different one-topping sundaes. If there are 7 flavors of ice cream, how many toppings are t

valentinak56 [21]

Answer:

Step-by-step explanation:

42/7 = 6

There are 6 toppings

7 0

3 years ago

Read 2 more answers