Answer:
What we know is that 30% of the group have brown hair and are girls. It means that in the other 70% we have the boys with brown hair, the other boys and the other girls.
In the case all the girls have brown hair, the 70% remaining would be boys. So 70% of then would have brown hair. (0.7*0.7=0.49 -> 49% of the children would be brown hair) so 49% (boys) and 30% (girls) are more than 50%..
Now, let's suppouse that 90% of the group are girls. It means 10% are boys and 70% of that 10% (=7%) are the boys in the group that have brown hair. Now 7% + 30% of the children have brown hair, wich isn't more than the half.
We have explained with two extreme cases that the information is not enough for making a precise answer
1. 360*0.40=144
so they said 40% reggie collected main mor than 40% collected so you need to do add like 360+144=504
the answer 504
2. you need to do new to old
the new is 15 old is 799
799-15=784x100
the high number is 799
so you need to do 799 divided by 100=7.99
now 784 divided by 7.99=98.12
the answer is 98.12
Well x=1 always unless it tells you other wise so 1+0.5 would equal 1.5 and so after that you keep adding so 1.5 + 0.5 equal 2 so you keep taking the previous answer and adding 0.5 to it
<u>Number of terms = 48</u>
<u>common difference = 1.5</u>
This question involves the concept of Arithmetic Progression.
- The formula for sum of an arithmetic progression series with first and last term given is;
=
(a + l)
where;
a = first term
l = last term
n = number of terms
- From the given sequence, we see that;
first term; a = 4
last term; l = 76
Sum of A.P;
= 1920
- Plugging in relevant values into the sum of an AP formula, we have;
1920 =
(4 + 76)
simplifying this gives;
1920 = 40n
n = 1920/40
n = 48
- Formula for nth term of an AP is;
=
+ (n - 1)d
where;
is first term
d is common difference
n is number of term
is the nth term in question
the 48th term is 76
Thus;
76 = 4 + (48 - 1)d
76 - 4 = 47d
72 = 47d
d = 72/47
d ≈ 1.5
Thus;
Number of terms = 48
common difference = 1.5
Read more at; brainly.com/question/16935540
Answer:

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