2 years ago

PLEASE HELP ME I WILL DO A POINTS GIVEAWAY AFTER ALL OF MY QUESTIONS ARE SOLVED

Mathematics

1 answer:

xz_007 [3.2K]2 years ago

8 0

Answer: 9

Step-by-step explanation:

i used math

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What is the mass, in grams, of the object being measured in the triple beam balance shown below?

muminat

Answer:

102.5 g

Step-by-step explanation:

The mass is the sum of the values indicated by the sliders:

100 g + 0 g + 2.5 g = 102.5 g

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3 years ago

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What is the value of the expression below?<br> (V9)2 +10

Wittaler [7]

to find the value of this expression, it would be easiest to use the distributive property.

(V9)2 +10

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3 years ago

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1+4=5 2+5=12 3+6=21 what is 8+11=

BlackZzzverrR [31]

8+11 is 19 Hope it helped

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3 years ago

Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.

fredd [130]

$\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

$\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

so the ODE is indeed exact and there is a solution of the form $F(x,y)=C$ . We have

$\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)$

$\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)$

$f'(y)=0\implies f(y)=C$

$\implies F(x,y)=x^2y^3+\ln(x+y^2)=C$

With $y(1)=2$ , we have

$8+\ln9=C$

$\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}$

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2 years ago

Use a factor and zero product property to solve the following equation 6x(x+4)=0

Rina8888 [55]

$6x(x+4)=0 \\
6x=0 \ \lor \ x+4=0 \\
x=0 \ \lor \ x=-4 \\
\boxed{x=0 \hbox{ or } x=-4}$

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3 years ago