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2 years ago

13

Need help on this math ASAP I will give the brainiest to the person who answers this correctly! Do the ones that are circled in

red please. (67 points to the person who answers this)

1 answer:

olasank [31]2 years ago

8 0

First box: 7/12, if 5/12 chance of making it then 7/12 of missing

Second box: 7/8=87.5%
Think about it like There is a 1 in 8 chance of landing on blue or 12.5% and the rest of the 100% would be on not getting blue

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If a radioactive isotope has a half-life of 6 hours and 12 milligrams is initially present, how much will

Serhud [2]

Answer:0.75 milligrams will be present in 24 hours

Step-by-step explanation:

Step 1

The formula for radioactive decay can be written as

N(t)=No (1/2)^(t/t 1/2)

where

No= The amount of the radioactive substance at time=0=milligrams

t 1/2= the half-life= 6 hours

t=24 hours

N(t) = the amount at time t

Step 2--- Solving

N(t)=No (1/2)^(t/t 1/2)

=N(t)=12 x ( 1/2) ^ (24/6)

= 12 x (1/2) ^4

= 12 x 0.0625

= 0.75 milligrams

3 0

2 years ago

Which pair of numbers have a GCF of 2? Choose all answers that are correct. A. 10 and 2 B. 4 and 6 C. 6 and 12 D. 2 and 24

il63 [147K]

A.
<span>GCF(10; 2) = 2 /</span>factors of 10: 1, 2, 5, 10; factors of 2: 1, 2/

B.
GCF(4; 6) = 2 /factors of 4: 1, 2, 4; factors of 6: 1, <span>2, 3, 6/</span>

C.
GCF(6; 12) = 6 /factors of 6: 1, 2, 3, 6; factors of 12: 1, <span>2, 3, 4, 6, 12/</span>

D.
GCF(2; 24) = 2 <span>/factors of 2: 1, 2; factors of 24: 1, <span>2, 3, 4, 6, 8, 12, 24/</span>

</span>Answer: A, B and D.

8 0

2 years ago

Read 2 more answers

Match each spherical volume to the largest cross sectional area of that sphere

zlopas [31]

Answer:

Part 1) $324\pi\ units^{2}$ ------> $7,776\pi\ units^{3}$

Part 2) $36\pi\ units^{2}$ ------> $288\pi\ units^{3}$

Part 3) $81\pi\ units^{2}$ ------> $972\pi\ units^{3}$

Part 4) $144\pi\ units^{2}$ ------> $2,304\pi\ units^{3}$

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

$A=324\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$324\pi=\pi r^{2}$

Solve for r

$r^{2}=324$

$r=18\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=18\ units$

substitute

$V=\frac{4}{3}\pi (18)^{3}$

$V=7,776\pi\ units^{3}$

Part 2) we have

$A=36\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$36\pi=\pi r^{2}$

Solve for r

$r^{2}=36$

$r=6\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=6\ units$

substitute

$V=\frac{4}{3}\pi (6)^{3}$

$V=288\pi\ units^{3}$

Part 3) we have

$A=81\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$81\pi=\pi r^{2}$

Solve for r

$r^{2}=81$

$r=9\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=9\ units$

substitute

$V=\frac{4}{3}\pi (9)^{3}$

$V=972\pi\ units^{3}$

Part 4) we have

$A=144\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$144\pi=\pi r^{2}$

Solve for r

$r^{2}=144$

$r=12\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=12\ units$

substitute

$V=\frac{4}{3}\pi (12)^{3}$

$V=2,304\pi\ units^{3}$

5 0

2 years ago

Read 2 more answers

In this equation, is (1, 5) a solution? *

monitta

Answer:

No (1,5) is not a solution

Step-by-step explanation:

if you try to solve this equation with the (1,5), you lay it out like 5 = 1/4 * 1 - 7. It turns into 5 = 1/4 - 7, because 1 times anything is that same number. Then you have to add 7 to both sides so that it cancels out on the right and you get 12 on the left. So you end up with the equation 12 = 1/4. This equation is not true, so therefore (1,5) is not a solution. Hope this helps :)

8 0

3 years ago

I DONT PAY ATTENTION PLEASE HELP ME AND EXPLAIN IF YOU FEEL LIKE IT

Molodets [167]

Answer: -5x

Step-by-step explanation: combine like terms hope this helps!

6 0

2 years ago