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3241004551 [841]
3 years ago
9

2,3 coordinates plot it.

Mathematics
1 answer:
zhenek [66]3 years ago
8 0
It should look like this

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What is the slope of the line that goes through (-2,-1) and (-3,-10)
liberstina [14]
The slope is 9
y1-y2 over x1-x2
or y2-y1 over x2-x1
3 0
3 years ago
Nvm, it took to long.
antiseptic1488 [7]
Sorry bro, maybe next time :/
4 0
3 years ago
A publisher needs to send many books to a local book retailer and will send the books in a combination of small and large boxes.
Paladinen [302]

Answer:

Answer:

\{ {{20x+30y=280} \atop {y=4x}} .{

y=4x

20x+30y=280

.

Where xx is the number of small boxes sent and yy is the number of large boxes sent.

Step-by-step explanation:

Let be xx the number of small boxes sent and yy the number of large boxes sent.

Since each small box can hold 20 books (20x20x ), each large box can hold 30 books (30y30y )and altogether can hold a total of 280 books, we can write the following equation to represent this:

20x+30y=28020x+30y=280

According to the information provided in the exercise, there were 4 times as many large boxes sent as small boxes. This can be represented with this equation:

y=4xy=4x

Therefore, the system of equation that be used to determine the number of small boxes sent and the number of large boxes sent, is:

\{ {{20x+30y=280} \atop {y=4x}} .{

y=4x

20x+30y=280

.

7 0
3 years ago
Please Help! In the figure below, triangle ABC is similar to PQR,as shown below:
castortr0y [4]

So triangle PQR is scaled at 4*triangle ABC
So if AB = 16 then PQ = 16*4 which is 64 so the third option

3 0
3 years ago
Read 2 more answers
What is the equation of the circle with center (2, –5) that passes through the point (–2, 10)?
Travka [436]
The standard equation of a circle is

(x-h)^2 + (y-k)^2 = r^2

where the center is at point (h,k)

From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be

r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241

Thus, the equation of the circle is

(x-2)^{2} + (y+5)^{2} =241
4 0
3 years ago
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