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Mariulka [41]
3 years ago
5

What is the slope of the line that goes through (-2,-1) and (-3,-10)

Mathematics
1 answer:
liberstina [14]3 years ago
3 0
The slope is 9
y1-y2 over x1-x2
or y2-y1 over x2-x1
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Find the value of the six trig functions given the triangle below.
Y_Kistochka [10]

\text{Here,}\\\\\text{Opposite side,}~ O = 2\\\\\text{Hypotenuse,}~ H   = \sqrt 5 \\\\\text{Adjacent side,}~ A = \sqrt{5-4} = \sqrt 1  =1  ~~ ;[\text{By using Pythagorean theorem}]\\\\\\\sin \theta = \dfrac{O}H = \dfrac 2{\sqrt 5}\\\\\\\cos \theta = \dfrac{A}{H} = \dfrac{1}{\sqrt 5} \\ \\\\ \tan \theta = \dfrac{O}{A} = \dfrac 21 = 2

csc \theta = \dfrac{1}{\sin \theta} = \dfrac{\sqrt 5}2\\\\\\\sec \theta = \dfrac{1}{\cos \theta} = \sqrt 5  \\\\\\\cot \theta = \dfrac 1{\tan \theta} = \dfrac 12

5 0
3 years ago
Write the equation of a line perpendicular to 2x + 3y = 4 and passing through (-3,-5).
Tasya [4]

Answer:

Step-by-step explanation:

A line perpendicular to the given line has a slope that is the negative inverse of the reference line.  

Rewrite the given equation in the format of y=mx+b, where mi is the slope and b is the y-intercept (the value of y when x = 0.

2x + 3y = 4

3y=-2x+4

y = -(2/3)X + (4/3)

The reference slope is -(2/3).  The negative inverse is (3/2), which will be the slope of a perpendicular line.  We can write the new line as:

y = (3/2)x + b

Any value of b will still result in a line that is perpendicular.  But we want a value of b that will shift the line so that it intersects the point (-3,-5).  Simply enter this point in the above equation and solve for b.

y = (3/2)x + b

-5 = (3/2)(-3) + b

-5 = -(9/2) + b

-5 = -4.5 + b

b = - 0.5

The equation of the line that is perpendicular to 2x + 3y = 4 and includes point (-3,-5) is

y = (3/2)x - 0.5

6 0
1 year ago
A basket holds at most 14 pounds of apples and oranges
Helen [10]
A.

B and C are wrong because x is more than or equal to 3.

D is wrong because y is the weight of oranges and cannot be negative.
7 0
3 years ago
Read 2 more answers
After t seconds, a ball in the air from the ground level reaches a height of h feet given by the equation h= 144t-16t^2 . After
Effectus [21]
H=0
Therefore:
144t-16t²=0
t (144-16t)=0
We have two equations:
1)
t=0    (when the ball is released)
2)
144-16t=0
-16t=-144
t=-144 / -16=9  (this is the time )

Answer: the ball hit the ground in 9 s. 
3 0
3 years ago
What is seven squared?
Goryan [66]
Ur answer is going to be 49
7 0
3 years ago
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