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Liono4ka [1.6K]
3 years ago
9

2x – 1 = y + 43y +1 = 3х – 2​

Mathematics
1 answer:
ehidna [41]3 years ago
3 0

Answer:x=4 y=3

Step-by-step explanation:

Let's solve your system by substitution.

2x−1=y+4;3y+1=3x−2

Step: Solve2x−1=y+4for y:

2x−1=y+4

2x−1+−y=y+4+−y(Add -y to both sides)

2x−y−1=4

2x−y−1+−2x=4+−2x(Add -2x to both sides)

−y−1=−2x+4

−y−1+1=−2x+4+1(Add 1 to both sides)

−y=−2x+5

−y

−1

=

−2x+5

−1

(Divide both sides by -1)

y=2x−5

Step: Substitute2x−5foryin3y+1=3x−2:

3y+1=3x−2

3(2x−5)+1=3x−2

6x−14=3x−2(Simplify both sides of the equation)

6x−14+−3x=3x−2+−3x(Add -3x to both sides)

3x−14=−2

3x−14+14=−2+14(Add 14 to both sides)

3x=12

3x

3

=

12

3

(Divide both sides by 3)

x=4

Step: Substitute4forxiny=2x−5:

y=2x−5

y=(2)(4)−5

y=3(Simplify both sides of the equation)

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Weights of American adults are normally distributed with a mean of 180 pounds and a standard deviation of 8 pounds. What is the
ahrayia [7]

Answer:

15.87% probability that a randomly selected individual will be between 185 and 190 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 180, \sigma = 8

What is the probability that a randomly selected individual will be between 185 and 190 pounds?

This probability is the pvalue of Z when X = 190 subtracted by the pvalue of Z when X = 185. So

X = 190

Z = \frac{X - \mu}{\sigma}

Z = \frac{190 - 180}{8}

Z = 1.25

Z = 1.25 has a pvalue of 0.8944

X = 185

Z = \frac{X - \mu}{\sigma}

Z = \frac{185 - 180}{8}

Z = 0.63

Z = 0.63 has a pvalue of 0.7357

0.8944 - 0.7357 = 0.1587

15.87% probability that a randomly selected individual will be between 185 and 190 pounds

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Answer: 16a^12 b^16

Step-by-step explanation:

Everything in the parenthesis to the 4th power.

2a^4= 16a

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b^4*4=b^16

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