What is 21 x 29 I need the answer please

Mathematics

2 answers:

Usimov [2.4K]3 years ago

6 0

Answer:

609

Step-by-step explanation:

LiRa [457]3 years ago

5 0

609

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Find the area of the triangle.

Yakvenalex [24]

A²+B²=C² then do Base x Hight decided by 2.

3 0

3 years ago

Read 2 more answers

HelloI need some assistance with this question. I provided an answer, but it was incorrect. The images are enclosed.

ycow [4]

Given:

There are given that the zeroes and degrees of the polynomial:

$\begin{gathered} \text{zeros:}-2,2,4 \\ \text{Degres:}3 \end{gathered}$

Explanation:

From the concept of a polynomial:

A polynomial has a as zero if and only if (x -a) is a factor of the polynomial.

Then,

From the given polynomial:

$f(x)=(x+2)(x-2)(x-4)$

Then,

$\begin{gathered} f(x)=(x+2)(x-2)(x-4) \\ f(x)=(x^2-2x+2x-4)(x-4) \\ f(x)=(x^2-4)(x-4) \\ f(x)=x^3-4x^2-4x+16 \end{gathered}$

Final answer:

Hence, the polynomial is shown below:

$f(x)=x^3-4x^2-4x+16$

6 0

2 years ago

If A+B+C=<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"

seraphim [82]

Answer:

$a + b + c = \pi \\ = > c= \pi - a - b \\ < = > \tan(c) = \tan(\pi - a - b) = -\tan(a + b)$

Step-by-step explanation:

we have:

$\tan(a) + \tan(b) + \tan(c) \\ = \tan(a) + \tan(b) - \tan(a + b) \\ = \tan( a) + \tan(b) - \frac{ \tan(a) + \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{ ( \tan(a) + \tan(b) ) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (1)$

we also have:

$\tan(a) \tan(b) \tan(c) \\ = - \tan(a) \tan(b) \tan(a + b) \\ = \frac{ -(\tan( a ) + \tan(b) ) \tan(a) \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{( \tan(a) + \tan(b)) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (2)$