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3 years ago

I NEED HELP PLEASE! TEST

Mathematics

2 answers:

SIZIF [17.4K]3 years ago

6 0

Answer:

Yes by SSS because you have the same hypotenuse and same hatch marks on other sides

Mrrafil [7]3 years ago

5 0

Answer:

its the second one (light blue)

Step-by-step explanation:

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suppose the sales tax rate is 9%. if the sales tax amount is $117 on a taxable item, what is the price of the item before tax?

Marrrta [24]

I'm pretty sure its $1,300

5 0

3 years ago

Which of the following statements describe the altitude of a parallelogram? A. It is the length of the parallelogram. B. It is p

bagirrra123 [75]

Because the altitude of parallelogram is perpendicular to the base and it is the height of the parallelogram so in this way every choices B. and C. are right sure
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hope helped

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3 years ago

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Math question I need help with it please help me !

never [62]

Answer:

96 degrees

Step-by-step explanation:

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2 years ago

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A company employee is planning a promotion party with her friends. She orders 6 pizzas for $7 each, 2 bowls of mixed salad for $

Allisa [31]

Answer:

$86 is she spending on the party.

Step-by-step explanation:

As per the statement: A company employee is planning a promotion party with her friends. She orders 6 pizzas for $7 each, 2 bowls of mixed salad for $12 each, and 4 cases of assorted soft drinks for $5 each.

⇒ 6 pizzas for $7 each

Total cost for 6 pizzas = $6 \times 7 = \$42$

2 bowls of mixed salad for $12 each.

Total cost for 2 bowls = $2 \times 12 = \$24$

and

4 cases of assorted soft drinks for $5 each.

Total cost for 4 cases of assorted soft drinks = $4 \times 5 = \$20$

She spending on party = Total cost for 6 pizzas + Total cost for 2 bowls + Total cost for 4 cases of assorted soft drinks

Substitute the values we get;

Total cost she spending on party = $\$42 + \$24 + \$20 =\$86$

4 0

3 years ago

Find the nth degree polynomial function with real coefficients satisfying the given conditions.

RUDIKE [14]

$\bf (x+1)(x-3)(x-2-4i)(x-2+4i)
\\\\
\textit{now, let's take a peek at }(x-2-4i)(x-2+4i)\\
\textit{and recall our }\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
(x-2-4i)(x-2+4i)\implies [(x-2)-(4i)][(x-2)+(4i)]
\\\\\
[(x-2)^2-(4i)^2]\implies [(x^2-2x+4)-(4^2\boxed{i^2})]
\\\\\
[(x^2-2x+4)-(16\cdot \boxed{-1})]\implies [(x^2-2x+4)+16]
\\\\
(x^2-2x+20)\\\\
-----------------------------$

$\bf thus
\\\\

\begin{array}{llll}
(x+1)(x-3)\\(x-2-4i)(x-2+4i)
\end{array}\implies (x+1)(x-3)(x^2-2x+20)
\\\\\\
(x^2-2x-3)(x^2-2x+20)\implies 
\begin{array}{llll}
x^4-2x^3+20x^2-2x^3\\+4x^2-40x+3x^2-6x+60
\end{array}
\\\\\\
x^4-4x^3+27x^2-46x+60$

4 0

2 years ago