Could a person with O+ blood have a daughter with AB+ blood? Explain.

The first stage of photosynthesis is the light dependent reactions. These reactions take place on the thylakoid membrane inside the chloroplast. During this stage light energy is converted to ATP (chemical energy) and NADPH (reducing power).

<span>The second stage of photosynthesis is the Calvin Cycle. These reactions occur in the stroma of the chloroplast. Energy from ATP and electrons from NADPH are used to convert carbon dioxide into glucose and other products.</span>

7 0

3 years ago

A semiconductor device that acts as a one-way valve to control the flow of electricity in electrical currents is a

Oxana [17]

pretty sure the answer is diode pls someone tell me if its wrong

7 0

3 years ago

Imagine that you attempted to recreate Mendel's work with garden peas. You began by crossing true breeding violet-flowered, tall

salantis [7]

Answer:

(a) 90

(b) 30

(c) 30

(d) 10

F2 data for stem length (tall:dwarf) is consistent with Mendel's law of segregation.

F2 data for stem length (tall:dwarf) and flower color (violet:white) is consistent with Mendel's law of independent assortment

Explanation:

The F2 phenotypes are supposed to be in 9:3:3:1 according to Mendelian law. The total number of F2 progeny is: 80 + 36 + 39 + 5 = 160

(a) Hence, the expected number of tall, violet plants will be:

9/16 x 160 = 90

(b) Expected number of tall, white plants will be:

3/16 x 160 = 30

(c) Expected number of dwarf, violet plants will be:

3/16 x 160 = 30

(d) Expected number of dwarf, white plants will be:

1/16 x 160 = 10.

Total number of tall F2 plants = 80 + 36 = 116

Total number of dwarf F2 plants = 39 + 5 = 44

Expected ratio of tall:dwarf plants according to Mendel = 3:1

Expected number of tall plants = 3/4 x 160 = 120

Expected number of dwarf plants = 1/4 x 160 = 40

Chi square $X^2$

= $\frac{(observed frequency - expected frequency)^2}{expected frequency}$

$X^2$ for tall = $\frac{(116 - 120)^2}{120}$

= 0.1333

$X^2$ for dwarf = $\frac{(44 - 40)^2}{40}$

= 0.40

Total $X^2$ = 0.1333 + 0.4

0.5333

Degree of freedom = n - 1

2 - 1 = 1

Tabulated $X^2$ (α = 0.05) = 3.841

Since the tabulated $X^2$ is more than the calculated $X^2$ , the hypothesis that the F2 data for stem length (tall:dwarf) is consistent with Mendel's law of segregation is accepted.

Observed Expected $X^2$

tall, violet flowers 80 90 $\frac{(80-90)^2}{90} = 1.11$

tall, white flowers 36 30 $\frac{(36-30)^2}{30} = 1.2$

dwarf, violet flowers 39 30 $\frac{(39-30)^2}{30} = 2.7$

dwarf, white flowers 5 10 $\frac{(5-10)^2}{10} = 2.5$

Total 160 160 7.51

Degree of freedom = 4 - 1 = 3

Tabulated $X^2$ (α = 0.05) = 7.815

The tabulated $X^2$ value is more than the calculated $X^2$ value. Hence, F2 data for stem length (tall:dwarf) and flower color (violet:white) is consistent with Mendel's law of independent assortment.

3 0

3 years ago