1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gtnhenbr [62]
3 years ago
12

There were 64 runners in the St Patrick's day race. If there were 20 more girls than boys how many were girls and how many were

boys
Mathematics
1 answer:
sleet_krkn [62]3 years ago
6 0

Answer:

42 girls 22 boys

Step-by-step explanation:

subtract 64 from 20

You might be interested in
Mara works in a music store and has a guitar on sale for 35% off. The guitars regular price is $630, what is the sale price?
lapo4ka [179]

Answer:

dfghfegfefehfgfe

Step-by-step explanation:

tyfvrfvewfgwvehgew e

3 0
3 years ago
If n = 3, what is the value of 2-n?<br> A 0.125<br> B 0.1667<br> C-6<br> D 8
antiseptic1488 [7]

Answer:

A... .................. ....

4 0
3 years ago
If the value of x=4, y=3 and z= -2 find the value of 2x+3z​
Oksana_A [137]

Answer:

<h2><em><u>2</u></em></h2>

Step-by-step explanation:

<em><u>To</u></em><em><u> </u></em><em><u>find</u></em><em><u> </u></em><em><u>value</u></em><em><u>:</u></em>

2x + 3z

<em><u>Given</u></em><em><u> </u></em><em><u>values</u></em><em><u>:</u></em>

x = 4, y = 3 and z = -2

<em><u>Solution</u></em><em><u>:</u></em>

2x + 3z

<em>(</em><em>Putting</em><em> </em><em>the</em><em> </em><em>values</em><em> </em><em>of</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>4</em><em> </em><em>and</em><em> </em><em>z</em><em> </em><em>=</em><em> </em><em>-2</em><em>)</em>

= 2(4) + 3(-2)

= 8 - 6

= <em><u>2 (Ans)</u></em>

8 0
3 years ago
Read 2 more answers
Again, please help. i dont know any of this
Levart [38]

\textrm {Cylinder volume :}

\mathrm {Volume = \pi r^{2}{h}}

\mathrm {Volume = 3.14 \times (\frac{4}{2})^{2} \times 3}

\mathrm {Volume = 3.14 \times 12}

\mathrm {Volume = 37.68cm^{3}}

\textrm {Rectangular prism volume :}

\mathrm {Volume = length \times width \times height}

\mathrm {Volume = 6 \times 5 \times 7}

\mathrm {Volume = 30 \times 7}

\mathrm {Volume = 210cm^{3}}

\textrm {Total volume of composite figure :}

\textrm {Volume of cylinder + volume of rectangular prism}

\mathrm {37.68 + 210}

\mathrm {247.68cm^{3}}

4 0
2 years ago
Read 2 more answers
Prove fermat's theorem for the case where f has a minimum at x0 (show f 0 (x0) = 0)
allochka39001 [22]
Suppose that some value, c, is a point of a local minimum point.

The theorem states that if a function f is differentiable at a point c of local extremum, then f'(c) = 0.

This implies that the function f is continuous over the given interval. So there must be some value h such that f(c + h) - f(c) >= 0, where h is some infinitesimally small quantity.
As h approaches 0 from the negative side, then: \frac{f(c + h) - f(c)}{h} \leq 0 \text{, where h is approaching 0 from the negative side}
As h approaches 0 from the positive side, then: \frac{f(c + h) - f(c)}{h} \geq 0

Thus, f'(c) = 0
6 0
4 years ago
Other questions:
  • 12y+d=−19y+t does anyone know the answer
    6·1 answer
  • Can anyone PLEASE HELP ME!!!????
    8·1 answer
  • What is n? Stick around for more points
    8·1 answer
  • Which value below will make 3-6x=21
    7·1 answer
  • Find the value of two numbers if their sum is 23 and their difference is 5
    10·1 answer
  • Chang has 2 shirts: a white one and a black one. He also has 2 pairs of pants, one blue and one tan. What is the probability, if
    11·2 answers
  • W=5, X=3, Y=4, Z=8<br><br> X(to the second power) + 4W-2Y (divided by) Z
    11·1 answer
  • ILL GIVE BRAINLEST!!!! A crafter is making a triangular flag. She has two sides of length 24 inches and 36 inches. What are the
    13·1 answer
  • Need help please due tommorw
    7·1 answer
  • Hey, Whats The answer please explain your answer marking brainliest:D......
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!