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SCORPION-xisa [38]
3 years ago
8

Find the value of X if m is parallel to n

Mathematics
1 answer:
S_A_V [24]3 years ago
4 0
It might be 85 I’m not totally sure
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Researchers working the mean weight of a random sample of 800 carry-on bags to e the airline. Which of the following best descri
Sphinxa [80]

Answer:

(E) The bias will decrease and the variance will decrease.

Step-by-step explanation:

Given that researchers working the mean weight of a random sample of 800 carry-on bags to e the airline.

We have to find out the effect of increasing the sample size on variance and bias.

We know as per central limit theorem, sample mean follows a normal distribution with mean = sample mean

and std deviation of sample mean = std error = \frac{std dev}{\sqrt{n} }

Thus std error the square root of variance is inversely proportional to the square root of sample size.

Also whenever we increase sample size the chances of bias would decrease as the sample size becomes larger

So correct answer is both bias and variation will decrease.

(E) The bias will decrease and the variance will decrease.

8 0
3 years ago
Find the values of a.b,andc in the table a= b= c=.
Svetach [21]

Answer:

a. is 1 and b is 2 and c is 3 I did it in algebra pay attention in class

4 0
2 years ago
A square is cut in half and the diagonal creating two equal triangles of each triangle has an area of 4.5 in.² what is the lengt
rusak2 [61]
8 Ft 9In i think dont kill me if its wrong
5 0
2 years ago
Find the area of the shape below
djverab [1.8K]
Break it down into a rectangle and triangle.
Area of rectangle is lw
One side of the rectangle is 8 (MA)
The other side is 6
Area is 8x6 = 48

Area of a triangle is 1/2 bh
h is 8
b is 10(AZ) - 6 (ME) = 4
Area of triangle is 1/2 (4 x 8) = 12

Add 48 and 12 to get 60
The area is 60
7 0
3 years ago
For a resistor in a direct current circuit that does not vary its resistance, the power that a resistor must dissipate is direct
Mrrafil [7]

THe problem is basically telling us: P=kV^2

where P is the power disappated and V^2 is our voltage squared.

\frac{1}{16}=k*14^2\implies\\ \frac{1}{16*196}=k \implies \\ \frac{1}{3136}=k

So, for the second example to find the power we simply have to plug k and our voltage back in, so:P=\frac{14^2*3^2}{14^2*6} \implies \\ P=\frac{9}{6}= \frac{3}{2}

6 0
3 years ago
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