The area of the quadrilateral is 16.80 square units if the diagonal divides the quadrilateral into two triangles.
<h3>What is quadrilateral?</h3>
It is defined as the four-sided polygon in geometry having four edges and four corners. It has one pair of opposite congruent angles and the diagonals of a kite are perpendicular.
We have a quadrilateral shown in the picture.
The diagonal divides the quadrilateral into two triangles
The area of the quadrilateral = area of the triangle ADC + area of the
triangle ADB
= (1/2)3.42×4.39 + (1/2)5.44×3.42
= 7.5069 + 9.3024
= 16.80 square units
Thus, the area of the quadrilateral is 16.80 square units if the diagonal divides the quadrilateral into two triangles.
Learn more about the quadrilateral here:
brainly.com/question/6321910
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1) Let's write out both expressions subtracting 4m²+2mn+8n² from 2m²+6mn+2n²
2) Note that when we subtract 4m^2 + 2mn + 8n^2 from 2m^2 + 6mn + 2n^2 we need to swap the sign by placing -1 outside the parentheses and then combine like terms adding those terms algebraically.
Answer:
The answer would be C
Step-by-step explanation:
You were going in the right direction but the problem was that you needed to subtract and not add. The formula should be y-y1 / x-x1 iirc. Hope this helped.
