All categories

2 years ago

5.(03.05)

Mathematics

2 answers:

shusha [124]2 years ago

7 0

Answer:

he runs for 39 min in 10 kilometres

Step-by-step explanation:

if he runs 10 kilometres

u add 4 10 times add if and u will find 39 min for 10 kilometres running

statuscvo [17]2 years ago

5 0

Answer:

f(x)=10-x/4

Step-by-step explanation:

this is the answer

You might be interested in

Help with five plz!!!!!

frutty [35]

Answer:

No there cannot be the same number of stickers on each page.

Step-by-step explanation:

If you want to find out how many stickers need to be in every page to be even you would add all the stickers up. 6+6+9+10+11= 42. Take the 42 and divide it by 5 to see how many stickers would go in each page. This will give you 8.4. However since this number is a decimal it can't be split evenly in whole stickers for each page. Meaning that it wouldn't be possible for each page to have a evenly distributed number of stickers per each page.

5 0

3 years ago

I need 5 questions answered!! PLEASE!

adoni [48]

Answer:

1. Yes

2. Distributive property

3. 2x+8y

4. I'm assuming its supposed to say 5(4x+3)-2x otherwise none of the options work, so the answer for that would be A

5. C

7 0

2 years ago

1/2 (x−8)+1=2( 1 8 x−1)

nalin [4]

Answer:

The solution for the given algebraic equation is $\frac{ - 2}{71}$

Step-by-step explanation:

Given algebraic equation as :

$\frac{1}{2}$ ( x - 8 ) + 1 = 2 ( 18 x - 1 )

Now solving the equation while opening the brackets

So, $\frac{1}{2}$ × x - $\frac{1}{2}$ × 8 + 1 = 2 × 18 x - 2

Or, $\frac{x}{2}$ - $\frac{8}{2}$ + 1 = 36 x - 2

or, $\frac{x}{2}$ - 4 + 1 = 36 x - 2

or, $\frac{x}{2}$ - 3 = 36 x - 2

or, $\frac{x}{2}$ - 36 x = - 2 + 3

Or, $\frac{x}{2}$ - 36 x = 1

or, $\frac{x - 72 x}{2}$ = 1

or, $\frac{- 71 x}{2}$ = 1

∴ 71 x = - 2

I.e x = $\frac{ - 2}{71}$

Hence The solution for the given algebraic equation is $\frac{ - 2}{71}$ Answer

7 0

3 years ago

Lucio quiere repartir su colección de estampillas entre la mayor cantidad de amigos pero de manera que todos reciban la misma ca

Daniel [21]

Answer:

Lucio podrá armar 5 grupos iguales de estampillas.

Step-by-step explanation:

El problema plantea un caso de distribución mediante la aplicación del divisor común mayor a todos los números involucrados. Para ello, primero debemos analizar los divisores de cada uno de estos números:

-30: divisible por 2, 3, 5, 6, 10, 15 y 30.

-75: divisible por 3, 5, 15, 25 y 75.

-160: divisible por 2, 4, 5, 8, 10, 16, 20, 32, 40, 80 y 160.

Así, podemos ver que el divisor común mayor a los tres números es 5, ya que 30, 75 y 160 dan como resultado un número entero tras ser divididos por 5.

Entonces, para poder repartir equitativamente sus estampillas entre la mayor cantidad de amigos posibles, deberá repartir 6 estampillas de animales, 15 estampillas de flores y 32 estampillas de ciudades a 5 amigos. De esta manera, Lucio podrá armar 5 grupos iguales de estampillas.

4 0

3 years ago

Use the information given in the diagrams to show that

Vlad1618 [11]

Answer:

d = k·sin(2θ)·sin(α)/(sin(θ)·sin(β))

Step-by-step explanation:

The Law of Sines tells us that sides of a triangle are proportional to the sine of the opposite angle. This can be used along with a trig identity to demonstrate the required relation.

<h3>top triangle</h3>

The law of sines applied to the top triangle is ...

BC/sin(A) = AC/sin(θ)

Triangle ABC is isosceles, so the base angles at B and C are congruent. Then the angle at vertex A is ...

∠A = 180° -θ -θ = 180° -2θ

A trig identity tells us the sine of an angle is equal to the sine of its supplement. That means the sine of angle A is ...

sin(A) = sin(180° -2θ) = sin(2θ)

and our above Law of Sines equation tells us ...

BC = sin(A)/sin(θ)·AC = k·sin(2θ)/sin(θ)

<h3>bottom triangle</h3>

The law of sines applied to the bottom triangle is ...

DC/sin(B) = BC/sin(D)

d/sin(α) = BC/sin(β)

Multiplying by sin(α) we have ...

d = BC·sin(α)/sin(β)

Using our expression for BC gives the desired relation:

d = k·sin(2θ)·sin(α)/(sin(θ)·sin(β))

7 0

1 year ago