The time needed at 2 meters per second for both rounds would be 100/2 s or 50 seconds. For the first lane he already used 50/1.5 -> 33.33 seconds, so he would need to cover the other 50 meters in exactly 16.67. 50m divided by the 16.67 seconds he has left means he has to swim at a speed of 3 meters per second.
Answer:
The area of this trapezoid is 28 square meters
Step-by-step explanation:
A=a+b
/2 h
This is how u would find horizontal and vertical asymptotes
Answer:
B
Step-by-step explanation:
First calculate BD using sine ratio in Δ BCD and the exact value
sin60° = 
, thus
sin60° = 
= 
= 
= ( cross- multiply )
2BD = 12
( divide both sides by 2 )
BD = 6
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Calculate AD using the tangent ratio in Δ ABD and the exact value
tan30° = 
, thus
tan30° = 
= 
= 
= ( cross- multiply )
AD = 6 ( divide both sides by )
AD = 6 → B
Answer:
yea its is
Step-by-step explanation:
