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Serga [27]
3 years ago
13

Plz help w these 5 problems. i’m begging anyone ! please please please .

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
7 0

Answer:

what the question

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Uhh, answer choices?

In any case, since \triangle KJL is inscribed in a semicircle, it is a right triangle (due to the inscribed angle theorem). Thus, by the Pythagorean theorem, KL=\sqrt{6^2+11^2}=\sqrt{157}. Now, the circumradius of a right triangle (the radius of the circle passing through all three of its vertices) is simply half its hypotenuse, so OJ=OK=OL=\frac{\sqrt{157}}{2}\approx \boxed{6.265}.

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3 years ago
DUDE ACTUALLY HELP PLEASE GIVING BRAINLIEST
Troyanec [42]

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