Dy/dx=1/2, 1/2, 1/2 etc
So this is a linear equation of the form y=mx+b where m=dy/dx=1/2 so
y=x/2 +b, now we can use any point to solve for the y-intercept, "b", I'll use (7,0)
0=7/2 +b
b=-7/2 so
y=x/2-7/2
y=(x-7)/2

Step-by-step explanation:


<em>Prologarithmize both parts of the equation:</em>

<u><em> Divide both parts of the equation by 2:</em></u>


Let log5 125 = x
Removing log you get 5^x = 125
Rewrite 125 as 5^3
Now 5^x = 5^3
x = 3