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Viefleur [7K]
3 years ago
5

Please help i just wanna see if it is D as the answer

Mathematics
1 answer:
3241004551 [841]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

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AlladinOne [14]

it would be 13

Step-by-step explanation:

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3 years ago
How can you use models to find factor
Karo-lina-s [1.5K]
Yes, it depends on what kind of model
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PLEASE HELP ILL GIVE FIVE STARS AND MARK BRAINLIEST
slega [8]

Ray is x years old.

Ron is y years old.

In 2 years, Ron will be two years older than now, so x+y+2 years old.

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3 years ago
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The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar
Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

\bar x represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

\chi^2_{\alpha/2}=19.022

\chi^2_{1- \alpha/2}=2.700

And replacing into the formula for the interval we got:

\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}

10.892 \leq \sigma^2 \leq 76.736

Now we just take square root on both sides of the interval and we got:

3.30 \leq \sigma \leq 8.76

So the best option would be:

3.30<σ<8.76

7 0
3 years ago
Alejandra correctly wrote the equation y – 3 = y minus 3 equals StartFraction 1 Over 5 EndFraction left-parenthesis x minus 10 r
Delvig [45]

Answer:

  y – 3 = 2(x – 10)

Step-by-step explanation:

In point-slope form, the equation is written ...

  y -k = m(x -h) . . . . . . . for line with slope m through point (h, k)

If only the slope changes, only the value just outside parentheses changes. When the point is (10, 3) and the new slope is 2, the new equation is ...

  y -3 = 2(x -10)

6 0
3 years ago
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