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Tamiku [17]
3 years ago
10

Find the derivative on the value of x=-4

title="y=(6x-5)\sqrt{8x-3}" alt="y=(6x-5)\sqrt{8x-3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Simora [160]3 years ago
8 0

\\ \sf\longmapsto y=(6x-5)\sqrt{8x-3}

\\ \sf\longmapsto y=6(-4)-5\sqrt{8(-4)-3}

\\ \sf\longmapsto y=-24-5\sqrt{-32-3}

\\ \sf\longmapsto y=-29\sqrt{-35}

\\ \sf\longmapsto y=-29\times 35i

\\ \sf\longmapsto y=-1015i

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